Pls answer! Dylan spots an airplane on radar that is currently approaching in a straight line, and
1 answer:
Answer:
13510 ft
Step-by-step explanation:
I have attached a triangle diagram to depict this situation.
From the diagram, we see that distance between A and B is denoted by x.
Now, from trigonometric ratios in this type of triangle, let's first find y.
6400/y = tan 36
y = 6400/tan 36
y = 8808.84 ft
Now, we can find x from;
6400/(8808.84 + x) = tan 16
6400/tan 16 = 8808.84 + x
22319.452 = 8808.84 + x
x = 22319.452 - 8808.84
x ≈ 13510 ft
You might be interested in
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is