Let f(x) = x² + 6x²-x+ 5 then ,
number to be added be P
then,
f(x) = x² + 6x²-x+ 5 +P
According to the qn,
(x+3) is exactly divisible by zero then,
R=0
comparing .. we get a= -3
now by remainder theorm
R=f(a)
0=f(-3)
0=(-3)² + 6(-3)²-(-3)+ 5 + P
0= 9 + 54 + 3 + 5 + P
-71=P
therefore, -71 should be added.
Hope you understand
Answer:
cups
Step-by-step explanation:
Given: A baker is using a cookie that calls for 2 
cups of flour to yield 36 cookies.
To find the number of flour will the baker need to make 90 cookies, we form a proportion.
Let's convert 2 to improper fraction.
Let "x" be the amount flour to make 90 cookies
<u>Amount of Flour</u> <u>Number of cookies</u>
36
x 90
Now form a proportion.
Now let's cross multiply, we get
Now let's simplify the fraction part, Here the GCF of 90 and 144 is 18, so dividing the fraction's numerator and the denominator by 18, we get
x = cups
So the baker needs cups to make 90 cookies.
Take 1 to the other side as negative
p/2=2
Take 2 to the other side and multiply it
2*2 is 4
So p is 4
See photo for answer
Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
