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s344n2d4d5 [400]
3 years ago
14

FInd the value of x/

Mathematics
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

x=18

Step-by-step explanation:

You might be interested in
\[f(x)=\sqrt{x ^4-16x ^{2}}\]
marusya05 [52]
f ( x ) =  \sqrt{ x^{4} -16 x^{2} }
a ) The domain:
x^4 - 16 x² ≥ 0
x² ( x² - 16 ) ≥ 0
x² - 16 ≥ 0
x² ≥ 16
x ∈ ( - ∞, - 4 ] ∪ [ 4 , + ∞ )
b ) f ` ( x ) = \frac{1}{2 \sqrt{x ^{4}-16 x^{2}  } } *  ( x^{4}-16 x^{2} )` =
= ( 2 x³ - 16 x ) / √(x^4 - 16 x²)
c ) The slope of the tangent line at x = 5:
f ` ( 5 ) = ( 2 * 125 - 16 * 5 ) / √ ( 625 - 400 ) = 170 / 15 = 34 / 3
The slope of the line normal to the graph at x = 5:
m = - 3 / 34 
4 0
3 years ago
What is the Least Common Multiple of x and 3x?
beks73 [17]

Answer:

3

Step-by-step explanation:

If you divide both numbers by x then it's just 1 and 3. LCM of 1 and 3 is 3

6 0
3 years ago
Read 2 more answers
Which statement is true?
diamong [38]

3 is correct , base is never equal to 1 cause all of solves of logarithm will be 0

7 0
3 years ago
Read 2 more answers
Which equation could be used to find the perimeter of an isosceles triangle, with two sides 13 cm long, a base 10 cm long, and a
AVprozaik [17]
Its A.
because if the base is 13 and 13 and the sides are 10 cm multiply and get A.
4 0
3 years ago
Foe the AP given by a1,a2,......,an,...with non zero common difference, the equation satisfied are
user100 [1]
The given sequence is
a₁, a₂, ..., a_{n}

Because the given sequence is an arithmetic progression (AP), the equation satisfied is
a_{n}=a_{1}+(n-1)d
where
d =  the common difference.

The common difference may be determined as
d = a₂ - a₁

The common difference is the difference between successive terms, therefore
d = a₃ - a₂ = a₄ - a₃, and so on..

The sum of the first n terms is
S_{n}= \frac{n}{2} (a_{1}+a_{n})

Example:
For the arithmetic sequence
1,3,5, ..., 
the common difference is d= 3 - 1 = 2.
The n-th term is
a_{n}=1+2(n-1)

For example, the 10-term is
a₁₀ = 1 + (10-1)*2 = 19
Th sum of th first 10 terms is
S₁₀ = (10/2)*(1 + 19) = 100



8 0
3 years ago
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