1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Effectus [21]
3 years ago
15

Right now could you help me on my rounding the nearest hundred

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Yes.

-- Look at the tens digit.
-- If it's 5 or more, add ' 1 ' to the hundreds digit.
-- If it's 4 or less, leave the hundreds digit alone.
-- Make the tens digit and the ones digit both zero.
You might be interested in
Six times the sum of a number and 7 equals 2
pogonyaev
6(x+7)=2
6(x)=-5
X=-0.83
7 0
3 years ago
A surveyor is conducting measures to see how wide a road is
drek231 [11]

Answer:

D) 45 ft

Step-by-step explanation:

The two triangles are shown below.

Given:

BC = 60 ft, CD = 24 ft and DE = 18 ft.

Since, the two triangles are similar, their corresponding sides are in proportion.

So, \frac{AB}{DE}=\frac{BC}{CD}=\frac{AC}{CE}

Now, consider the proportion of sides,

\frac{AB}{DE}=\frac{BC}{CD}\\AB=\frac{BC}{CD}\times DE\\AB=\frac{60}{24}\times 18\\AB=\frac{60\times 18}{24}=45\ ft

Therefore, the distance between A and B is 45 ft.

8 0
3 years ago
If a- b= 2 and ab= 15 then a3-b3?<br>a) 30 b) 98 c) 20 d) 60<br>full explanation please​
krek1111 [17]

Answer:

C) 20

Step-by-step explanation:

ab=15

5*3 = 15

which is a and which is b

a - b = +2

5 - 3 = + 2

------------------

a = 5 and

b = 3

------------------

a3-b3 = 53 - 33 = 20

7 0
2 years ago
Read 2 more answers
Help me Please help please
MA_775_DIABLO [31]
The answer is 37/6 or by decimal form 6.16
3 0
3 years ago
According to an​ airline, flights on a certain route are on time 80​% of the time. Suppose 17 flights are randomly selected and
tensa zangetsu [6.8K]

Answer:

a) Check Explanation

b) Probability that 11 out of the 17 randomly selected flights are on time = P(X = 11) = 0.0680

c) Probability that fewer than 11 out of the 17 randomly selected flights are on time

= P(X < 11) = 0.0377

d) Probability that at least 11 out of the 17 randomly selected flights are on time

= P(X ≥ 11) = 0.9623

e) Probability that between 9 and 11 flights, inclusive, out of the randomly selected 17 are on time = P(9 ≤ X ≤ 11) = 0.1031

Step-by-step explanation:

a) How to know a binomial experiment

1) A binomial experiment is one in which the probability of success doesn't change with every run or number of trials. (Probability of each flight being on time is 80%)

2) It usually consists of a number of runs/trials with only two possible outcomes, a success or a failure. (It's either the flights are on time or not).

3) The outcome of each trial/run of a binomial experiment is independent of one another.

All true for this experiment.

b) Probability that exactly 11 flights are on time.

Let X be the random variable that represents the number of flights that are on time out of the randomly selected 17.

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = 17 randomly selected flights

x = Number of successes required = number of flights required to be on time

p = probability of success = Probability of a flight being on time = 80% = 0.80

q = probability of failure = Probability of a flight NOT being on time = 1 - p = 1 - 0.80 = 0.20

P(X = 11) = ¹⁷C₁₁ (0.80)¹¹ (0.20)¹⁷⁻¹¹ = 0.06803777953 = 0.0680

c) Probability that fewer than 11 flights are on time

This is also computed using binomial formula

It is the probability that the number of flights on time are less than 11

P(X < 11) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.0376634429 = 0.0377

d) Probability that at least 11 out of the 17 randomly selected flights are on time

This is the probability of the number of flights on time being 11 or more.

P(X ≥ 11) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17)

= 1 - P(X < 11)

= 1 - 0.0376634429

= 0.9623365571 = 0.9623

e) Probability that between 9 and 11 flights, inclusive, are on time = P(9 ≤ X ≤ 11)

This is the probability that exactly 9, 10 or 11 flights are on time.

P(9 ≤ X ≤ 11) = P(X = 9) + P(X = 10) + P(X = 11)

= 0.0083528524 + 0.02672912767 + 0.06803777953

= 0.1031197592 = 0.1031

Hope this Helps!!!

3 0
3 years ago
Other questions:
  • Use De Moivre’s Theorem to compute the following: <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%288cos%284%20%5Cpi%20%2F5%
    11·1 answer
  • 2x+3=5x-42 what is the number that belongs in the green box
    12·1 answer
  • Which property is used to solve 3X31X10
    8·1 answer
  • Help with this problem please
    11·2 answers
  • 15. Cedric lives at one end of Main Street, and Landon lives at the other end of the street. Main Street is 6.02 Kilometers long
    7·1 answer
  • PLEASE URGENTLY ANSWER THESE 2 QUESTIONS, I WILL PROVIDE MORE POINTS AND CROWN YOU BRAINLIEST IF YOU DO!!!
    13·1 answer
  • Find the volume of the following shapes. Round to tenths and don’t forget the units. Show your work!
    6·1 answer
  • Pls help me! I will mark brainliest if you are correct
    12·2 answers
  • NO LINKS PLEASE!<br> Determine the measure of
    15·2 answers
  • If 180 kg of sugar is to be divided into 3 quantities of ratio 2:3:4 find the smallest and largest quantities.​
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!