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Effectus [21]
3 years ago
15

Right now could you help me on my rounding the nearest hundred

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Yes.

-- Look at the tens digit.
-- If it's 5 or more, add ' 1 ' to the hundreds digit.
-- If it's 4 or less, leave the hundreds digit alone.
-- Make the tens digit and the ones digit both zero.
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Enter the value, as a mixed number in simplest form, in the box. |2 1/3| = ?
Fittoniya [83]
Unclear of the question, but the value is already as a mixed fraction. The value of absolute value is just the distance from zero. So, |-4|=4 or |6|=6
|2 \frac{1}{3} |  =  2 \frac{1}{3}
7 0
3 years ago
QUESTION: Determine if the statement is true or false? if false give an counterexample.
Jobisdone [24]

Answer:

  • False

Step-by-step explanation:

<u>Actual question is:</u>

  • logf 4(3d) + log4 1 = log4 3d

<u>Solution:</u>

  • logf 4 + logf (3d)  + 0 = log4 (3d)
  • logf 4 + logf (3d) = log4 (3d)

<u>If we assume f = 4, then</u>

  • log4 4 + log4 (3d) = log4 (3d)
  • log4 4 = 0

but log4 4 = 1

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Therefore the statement is False

5 0
2 years ago
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
2 years ago
Can I have the answer to this question please
Crazy boy [7]

answer = 9c²d^8

(3cd^4)^2

=(3)^2 × c^2 × (d^4)^2

=9×c^2×d^8 ----law of indices (a^m)^n = a^mn

=9c²d^8

6 0
3 years ago
Which fraction has the same value as 2 3<br> 8
Alik [6]

Answer:

The Answer : 19/8 Not sure if I'm correct

7 0
3 years ago
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