Right now could you help me on my rounding the nearest hundred

1 answer:

3 0

Yes.

-- Look at the tens digit.
-- If it's 5 or more, add ' 1 ' to the hundreds digit.
-- If it's 4 or less, leave the hundreds digit alone.
-- Make the tens digit and the ones digit both zero.

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If (6^2]^p = 6^10, what is the value of p? <br> A.) 2 <br> B.) 3<br> C.) 4<br> D.) 5

kvv77 [185]

If u raise a power to another power, then u multiply the powers. In this case, u can simplify to 6^2p =6^10

Now you have like bases, so you can set the powers equal to each other. So now, 2p=10. Now p=5

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(a) no
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Step-by-step explanation:

"Of the order x^2" means the dominant behavior matches that of x^2 as x gets large. For polynomial functions, the dominant behavior is that of the highest-degree term.

For other functions, the dominant behavior will typically be governed in some other way. Here, the rate of growth of the x·log(x) function is determined by log(x), which has decreasing slope as x increases.

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Nataly_w [17]

Answer:

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Step-by-step explanation:

Factor the numerator and denominator and cancel the common factors.

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