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3 years ago

Right now could you help me on my rounding the nearest hundred

1 answer:

3 0

Yes.

-- Look at the tens digit.
-- If it's 5 or more, add ' 1 ' to the hundreds digit.
-- If it's 4 or less, leave the hundreds digit alone.
-- Make the tens digit and the ones digit both zero.

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X^2 + 18x + c= 25 + c

ryzh [129]

Answer:

2 real solutions

Step-by-step explanation:

x^2+18x+c-25-c=0

x^2+18x-25

D=18^2 - 4 x 1 x (-25)

D=424

D> 0 --> 2 real solutions

8 0

2 years ago

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?

Svetach [21]

Answer:

Hence, the domain of the function is:

{4,7}

Step-by-step explanation:

We are given the range of the function:

$f(k)=k^2+2k+1$ as {25,16}

The function f(k) could also be written as:

$f(k)=k^2+2k+1=k^2+k+k+1\\\\f(k)=k(k+1)+1(k+1)\\\\f(k)=(k+1)(k+1)\\\\f(k)=(k+1)^2$

The range is the value of the function at some k.

if f(k)=25 then we have to find the value of k.

$f(k)=25=5^2=(k+1)^2$

on taking square root on both side we have:

$k+1=5\\\\k=5-1\\\\k=4$

if f(k)=64 then we have to find the value of k.

$f(k)=64=8^2=(k+1)^2$

on taking square root on both side we have:

$k+1=8\\\\k=8-1\\\\k=7$

Hence, the domain of the function is:

{4,7}

7 0

3 years ago

Read 2 more answers

What’s 20/10 simplified??

KATRIN_1 [288]

20/10 IF SIMPLIFIED IS 2/1 MEANS 2

7 0

2 years ago

Read 2 more answers

Simplify by factoring. Assume that all expressions under radicals represent nonnegative numbers.

NeTakaya

$\sqrt{96x^2y}=\sqrt{16\cdot6\cdot x^2\cdot y}=\sqrt{16}\cdot\sqrt6\cdot\sqrt{x^2}\cdot\sqrt{y}\\\\=4\cdot\sqrt6\cdot x\cdot\sqrt{y}=4x\sqrt{6y}$

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$\left(x^4y^4\right)^\frac{1}{3}=\left(x^4\right)^\frac{1}{3}\left(y^4\right)^\frac{1}{3}=x^{4\cdot\frac{1}{3}}y^{4\cdot\frac{1}{3}}=x^\frac{4}{3}y^\frac{4}{3}=x^{1+\frac{1}{3}}y^{1+\frac{1}{3}}\\\\=x^1x^\frac{1}{3}y^1y^\frac{1}{3}=x\sqrt[3]{x}\cdot y\sqrt[3]y=xy\sqrt[3]{xy}$

6 0

2 years ago

Please help me with this!!!!!

vekshin1

Answer:

y = 4

Step-by-step explanation:

Note that A and B have the same x-coordinate: 1. This means that AB is a vertical line through x = 1. The perpendicular bisector of AB must be a horizontal line situated halfway between y = 3 and y = 5. Thus, it's just y = 4.

Review: y = 4 bisects AB and represents a horizontal line.

6 0

2 years ago