You have two angles congruent, plus a side that's NOT between them.
I guess you'd call that situation " AAS " for "angle-angle-side".
That's what you have, and it's NOT enough to prove the triangles
congruent. There can be many many different pairs of triangles
that have AAS = AAS.
So there's no congruence postulate to cover this case, because they're
not necessarily.
Answer: 256
Step-by-step explanation:
Answer:
x = 31, x = 19
Step-by-step explanation:

A -2
B -5
I think I might be wrong
Answer:
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Step-by-step explanation:
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