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Alekssandra [29.7K]
2 years ago
7

Solve for x: 1 04>x>7 0 4 0-2 >x> 1 -2

Mathematics
1 answer:
Luda [366]2 years ago
8 0

Answer:

Your answer is in Step by Step

Step-by-step explanation:

=104x^7040-2x^1-2

We move all terms to the left:

-(104x^7040-2x^1-2)=0

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Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
10 months ago
A medical records clerk gathers data about patients with broken bones. It is found that 3/5 of the medical records are for broke
beks73 [17]
3/5 = x/1357
Cross multiple
5x = 4071
Divide by 5
X = 814 records of broken bone
4 0
3 years ago
Given the sequence: -1, 2, 5, 8 what is a(2)?
makvit [3.9K]

Answer:

Your just going to keep adding 3 and the 2 is there because you had negative -1 and then you added 3 so hope this helps probably not what you looking for but hope this helps. Have a good day.

Step-by-step explanation:

6 0
2 years ago
Marisol has enough tile to cover a square portion of her patio with an area of 225 ft2. What will be the side lengths of her des
Anit [1.1K]

Answer:

Side lengths = 15 ft²

Step-by-step explanation:

Given:

Area of square = 255 ft²

Find:

Side lengths

Computation:

Area of square = side x side

Area of square = 255 ft²

Side lengths = √Area of square

Side lengths = √255

Side lengths = 15 ft²

4 0
3 years ago
Question 1: Find the amount of the FICA deduction: $37890 annually.
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Answer:

b....j..j.jm..e.e.e i didnt get it

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