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3 years ago

Find the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)

1 answer:

7 0

The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is $(\frac{-17}{5} ,\frac{2}{5} )$

Explanation :

the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)

Apply section formula to find coordinates of point Q

$(\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n} )$

Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)

Substitute all the values inside the formula

$(\frac{2(2)+3(-7)}{2+3} , \frac{2(4)+3(-2)}{2+3} )\\\\(\frac{-17}{5} ,\frac{2}{5} )$

The coordinates of point Q is $(\frac{-17}{5} ,\frac{2}{5} )$

Learn more : brainly.com/question/13878373

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USPshnik [31]

Answer:

0.2

Step-by-step explanation:

30/150 = 1/5 = 0.2

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2 years ago

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How many square tiles of side 10cm each will be needed to tile a floor which is 300cm long and 150cm wide?

S_A_V [24]

Step 1

Find the area of one tile

we know that

the area of a square is

$A=b^{2}$

where b is the length side of the square

In this problem

$b=10\ cm$

Substitute

$A=10^{2}=100\ cm^{2}$

Step 2

Find the area of the floor

The area of a rectangle is equal to

$A=LW$

where

L is the length of the rectangle

h is the width of the rectangle

In this problem

$L=300\ cm$

$W=150\ cm$

Substitute

$A=300*150=45,000\ cm^{2}$

Step 3

Find the number of tiles needed

by proportion

$\frac{1}{100} \frac{tile}{\ cm^{2}} =\frac{x}{45,000} \frac{tile}{\ cm^{2}} \\ \\x=45,000/100 \\ \\x=450 \ tiles$

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<u>the answer is</u>

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3 years ago

HELP ME PLEASE... WILL GIVE BRAINLIEST. WORTH A LOT OF POINTS

timofeeve [1]

Answer:

A) The solution is x = 2 and y = 2

B) The graphs would intersect at the point (2, 2).

Step-by-step explanation:

We start with the system of equations:

y = 6*x - 10

y = 2*x - 2

To solve this, the first step is to isolate one of the variables in one of the equations.

Here we can see that the variable "y" is already isolated in both equations, so we can skip that step.

Now we can "replace" the "y" in one of the equations for the correspondent expression in the other.

we can write:

(6*x - 10) = y

and for the second equation, we know that y = 2*x - 2

So replacing that, we get:

6*x - 10 = 2*x - 2

Now we can solve this for x.

6*x - 2*x = - 2 + 10

4*x = 8

x = 8/4 = 2

Now to find the value of y, we can just input this value of x in any one of the two equations:

y = 6*2 - 10 = 12 - 10 = 2

y = 2*2 - 2 = 4 - 2 = 2

So the solution of the system is:

x = 2, y = 2

B) Because the solution of the system is the ordered pair (2, 2), this means that the ordered pair belongs to the graph of both lines, then we can conclude that these lines will intersect at that point (the one that is common to both lines). Actually, when we have a system of equations, graphing both equations and finding the points where the graphs intersect is one method to estimate the solution of the system.

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Vilka [71]

What's the question here?

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3 years ago

Use the present value formula to determine the amount to be invested now, or the present value needed.

Vladimir79 [104]

Answer:

The value needed now is $102,296.60

Step-by-step explanation:

Here, we want to calculate the present value needed.

We shall be using the formula for compound interest here

Mathematically;

A = I(1 + r/n)^nt

According to the question;

I is the initial amount which is what we want to calculate

A is the accumulated amount with interest = 140,000

r is the interest rate = 8% = 8/100 = 0.08

n is the number of times interest is compounded which is 4, since it is quarterly

t is the number of years = 2

Substituting these values, we have ;

140,000 = I(1 + 0.08/2)^(4 * 2)

140,000 = I(1.04)^8

I = 140,000/(1.04)^8

I = 102,296.62870027774

Which is I = $102,296.60 to the nearest cent

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