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maria [59]
3 years ago
14

Use the Pythagorean Theorem to determine the missing hypotenuse of a right triangle given the side lengths a= 7 in. and b = 9 in

. Round your answer to the nearest hundredth if necessary

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0

Answer:

11.40

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

7² + 9² = c²

49+ 81 = 130

Square root of 130= 11.40

igor_vitrenko [27]3 years ago
5 0

Answer:

11.40

Step-by-step explanation:

a^2 + b^2 = c^2

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The mountain road was distinctly -------: it twisted
Dima020 [189]

(C) "serpentine"

Serpentine is a winding word. The phrase would read "The mountain road was distinctly serpentine: it twisted back and forth along the contours of the hillside" if this term were added to the text.

The comma denotes that the meaning of the omitted phrase will be clarified in the second clause of the sentence. Because a winding road does actually curve "back and forth," the word "serpentine" matches the text. The answer is not (A).

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Here's another question with an answer similar to this about passage analysis: brainly.com/question/3521530

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4 0
2 years ago
What is 10xy - 15y in factored form
Oduvanchick [21]

The factored form of 10xy - 15y is 5y(2x - 3)

<em><u>Solution:</u></em>

Given that, we have to write the given expression in factored form

<em><u>Given expression is:</u></em>

10xy - 15y

To find the factored form, let us first find the greatest common factor of 10 and 15

The factors of 10 are: 1, 2, 5, 10

The factors of 15 are: 1, 3, 5, 15

Then the greatest common factor is 5

Thus, factor out 5 from given expression

10xy - 15y = 5(2xy - 3y)

Now factor out the common term "y"

10xy - 15y = 5(2xy - 3y) = 5y(2x-3)\\\\10xy - 15y = 5y(2x-3)

Thus the factored form is found

3 0
3 years ago
5 + 3 - c (when c=8)
ludmilkaskok [199]

Answer:

0 is your answer

Step-by-step explanation:

5 0
3 years ago
PLEASE PLEASE PLEASE HELP ME
lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ \frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}

∵ DE : CD = 5 : 3

∴ \frac{KD}{KC}=\frac{5}{3}

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ \frac{KE}{KD}=\frac{5}{3}

∴ \frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}

∴ KC + 8 = \frac{25}{9}KC

∴ \frac{25}{9}KC - KC=8

∴ \frac{16}{9}KC=8

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0
3 years ago
Solve the problem by using a common denominator: 5/10 + 34/100
Lisa [10]
To find a common denominator, you would multiply the first number by 10 both top and bottom, to get 50/100. Now that they are both 100 at denominator, you can add 50 and 34 to get 84/100, or simplify that to 21/25.
8 0
4 years ago
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