Find measure angle B

The cost of 20⅕ oranges is rs 300,what is the cost of a kg oranges?

JulijaS [17]

Answer:

weight not defined

Step-by-step explanation:

The cost of 20⅕ oranges is rs 300 ,what is the cost of a kg oranges?

HOW ARE WE SUPPOSE TO KNOW THE WEIGHT IF ONLY THE PRICE IS GIVEN

5 0

3 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

all real numbers are solutions

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

no solution

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

F(x) = (1/4)^x. for x = -3

Trava [24]

Plug in -3 for x into the equation.

(1/4)^-3

And solve

(1/4)^-3 = 64

7 0

3 years ago

Read 2 more answers

Question 4 of 10 A construction worker needs to put a rectangular window in the side of a building. He knows from measuring that

vagabundo [1.1K]

Answer:

❝ D. 13 feet ❞

Step-by-step explanation:

Here,

Window is in the rectangular shape.
Measure of its one diagonal is 13 feet.

According to the properties of rectangle,

→ Diagonals of a rectangle are equal.

So, here the length of other diagonal will be 13 feet too.

7 0

3 years ago

Factor the following: 1. 5(a+3)²- (a+3 2. p²- 6 - q · (p²- 6)²

scoundrel [369]

Answer:

1. $(a + 3)(5a-14)$

2. $(p^2-6)[1-q(p^2-6)]$

Step-by-step explanation:

1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.

Then the expression. $5(a + 3)^2- (a + 3)$ remains as:

$(a + 3)(5 (a + 3) -1)\\\\(a + 3)(5a +15 -1)\\\\(a + 3)(5a-14)$

2. The first thing to do to factor the expression is to take the expression $p^2 -6$ as its common factor with its lowest exponent.

Then the expression $p^2- 6 - q(p^2- 6)^2$ remains as:

$(p^2-6)[1-q (p^2-6)]$

8 0

3 years ago