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Diano4ka-milaya [45]
3 years ago
14

Calvin Butterball is driving along the highway. He starts up a long, straight hill. 114 meters from the bottom of the hill Calvi

n's car runs out of gas. He doesn't put on the brakes, so the car keeps rolling for awhile, coasts to a stop, then start rolling backwards. He finds that his distances from the bottom of the hill 4 and 6 seconds after he runs out of gas are 198 and 234 meters, respectively. b.Write an equation expressing Calvin's distance from the bottom of the hill in terms of the number of seconds which have elapsed since he ran out of gas.
Mathematics
1 answer:
lbvjy [14]3 years ago
4 0
The answer is 6hours in 122 minutes do umknow
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Please help !!
shutvik [7]

Given:

The limit problem is:

\lim_{x\to 3}(x^2+8x-2)

To find:

The limit of the function by using direct substitution.

Solution:

We have,

\lim_{x\to 3}(x^2+8x-2)

Applying limit, we get

\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2

\lim_{x\to 3}(x^2+8x-2)=9+24-2

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\lim_{x\to 3}(x^2+8x-2)=31

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mars1129 [50]
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Write an equation for the line passing through the points (-5,15) and (20,25). Show how you found your answer.
olasank [31]

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-5, 15) and (20, 25). substitute:

m=\dfrac{25-15}{20-(-5)}=\dfrac{10}{25}=\dfrac{2}{5}\\\\y-15=\dfrac{2}{5}(x-(-5))\\\\y-15=\dfrac{2}{5}(x+5)\qquad|\text{use distributive property}\\\\y-15=\dfrac{2}{5}x+2\qquad|\text{add 15 from both sides}\\\\y=\dfrac{2}{5}x+17\qquad|\text{multiply both sides by 5}\\\\5y=2x+85\qquad|\text{subtract 2x from both sides}\\\\-2x+5y=85\qquad|\text{change the signs}\\\\2x-5y=-85

Answer:

point-slope form: y-15=\dfrac{2}{5}(x+5)

slope-intercept form: y=\dfrac{2}{5}x+17

standard form: 2x-5y=-85

7 0
3 years ago
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saul85 [17]

Answer:

-1: -1, 1

-12: -12, -6, -4, -3, -2, -1, 1, 2, 3, 4, 6, 12

Step-by-step explanation:

6 0
3 years ago
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