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Blababa [14]
2 years ago
9

25 POINTS!!!!! REAL ANSWERS ONLY!!!!!!!! I WILL REPORT LINKS AND FAKE/WRONG ANSWERS!!!!!!!​

Mathematics
1 answer:
Nonamiya [84]2 years ago
3 0

Answer:

7.

lateral surface area of traingular prism=perimeter of traingle ×length=[5+3+4]×6=72cm²

curved surface area=2[area oftraingle]=2×1/2×4×3

=12cm²

now

total surface area=72cm²+12cm²=84cm²

8.

volume of traingular prism=area of traingle ×length

=1/2×12×3.4×4=81.6cm³

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mestny [16]

Answer:

a) 2^{3}

b) 2^{5}

c) 2^{8}

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e) 2^{4} + 2^{3}

Step-by-step explanation:

a) 8 = 2 x 2 x 2

b) 32 = 2 x 2 x 2 x 2 x 2

c) 256 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2

d) 5 x 2^3 / 64 = 5 x 8 / 64

                        = 40/64

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Step-by-step explanation:

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Jerry buys a case of bar soap. The case holds 12 packages. Each package contains four bars of soap. If each bar of soap is four
Sonja [21]

Answer:

The answer is D. 12 pounds

Step-by-step explanation:

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A study showed that 14 of 180 publicly traded business services companies failed a test for compliance with Sarbanes-Oxley requi
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Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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For this problem, we have that:

n = 180, \pi = \frac{14}{180} = 0.0778

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 - 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.0387

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.0778 + 1.96\sqrt{\frac{0.0778*0.9222}{180}} = 0.1169

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4 0
3 years ago
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Answer:

D. 6

Step-by-step explanation:

Let's first find x :-

\sf 3 + 2x + 22 = x + 17

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Now that we found x, let's find QR :-

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Therefore, QR = 6 !!!

4 0
2 years ago
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