All categories

3 years ago

One serving of 18 crackers has 200 calories. How many calories are in 90 crackers?

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

Answer: 1,000 calories

Work: 90/18=5 and 5*200=1,000

Svetradugi [14.3K]3 years ago

4 0

Answer:

1000 calories because if 18 cracker are 200 calories and you divied 90 by 18 you get 5 and 5 x 200=1000 calories

You might be interested in

Geometry: please only comment if you know the answer I need help with this please

stich3 [128]

Answer:

Step-by-step explanation:

8 0

2 years ago

There are _ total possible outcomes.

Ede4ka [16]

Answer:

20 possible outcomes

Step-by-step explanation:

4 0

2 years ago

Someone please help!!

Dafna1 [17]

Answer:

SAS means "Side, Angle, Side"

ASA means "Angle , Side, Angle"

AAS means "Angle, Angle, Side"

HL stangs for "Hypotenuse, Length"

Step-by-step explanation:

SAS is when we have two sides meeting and forming an angle between them.

ASA is when we know two angles and a side between the angles.

AAS is when we know two angles and a side which is not between the angles.

HL means that: two triangles are congruent if the hypotenuse of one triangle is equal to the hypotenuse of the other and if one leg of a triangle is equal to a leg of another triangle.

*Note: The pictures are attached here below.

3 0

3 years ago

A store has 510 pieces of candy. The candy is in bags of 10 to sell. How many bags of candy will the store need?

jok3333 [9.3K]

Answer:

Step-by-step explanation:

510 pieces of candy, and candies can be sold in bags of 10.

Dividing 10 into 510 will give us our answer, which is 51.

7 0

3 years ago

Read 2 more answers

Find f · dr c for the given f and

ruslelena [56]

Parameterize the path $\mathcal C$ by

$\mathbf r(t)=x(t)\,\mathbf i+y(t)\,\mathbf j$

with

$x(t)=3\cos t$
$y(t)=3\sin t$

and $0\le t\le\pi$ . Then

$\displaystyle\int_{\mathcal C}\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=\pi}\mathbf f(x(t),y(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt$
$=\displaystyle\int_0^\pi(9\cos^2t\,\mathbf i+9\sin^2t\,\mathbf j)\cdot(-3\sin t\,\mathbf i+3\cos t\,\mathbf j)\,\mathrm dt$
$=27\displaystyle\int_0^\pi(\cos t\sin^2t-\sin t\cos^2t)\,\mathrm dt=-18$

5 0

3 years ago