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Alinara [238K]
3 years ago
8

5. Seismologists use the Richter scale to measure the magnitudes and intensity of earthquakes that occur all over the earth. (se

e below, some info about Richter scales, and intensity formula)
Let’s say an earthquake hit Los Angeles, CA and had a magnitude of 3.4. If another earthquake hit Atlanta, GA and was a magnitude of 1.2, then how much more intense was the earthquake in LA?
Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

Answer:

158.49

Step-by-step explanation:

10^(3.4 - 1.2) = 158.48931924611

round to 158.49

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Which fraction is greater 2/5 or 4/10
loris [4]

They are equal. 2/5 is 4/10.

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3 years ago
Can we conclude that these two triangles are congruent?
Aleonysh [2.5K]

Answer:

Yes,

Step-by-step explanation:

because two sides are shown equal to each other, a and b. Also two angles are equal to each other, x and y. Once you know two angles or two sides are equal so is the third side.

Another way is SAS (side angle side). There is side a, angle y, and side b. These are shown on both triangles.

Therefore, we can conclude these two triangles are congruent.

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3 years ago
A class of 24 students is planning a field trip to a science museum. A nonrefundable deposit of $50 is required for the day-long
GaryK [48]
Can I see the graphs ?
3 0
3 years ago
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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

5 0
3 years ago
3x - 6y = 27<br><br> 3x + 4y = 17
11111nata11111 [884]

Answer: {x,y} = {27/4,-47/8}

3 0
3 years ago
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