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2 years ago

10

Mrs. Wheeler wants to cook a turkey for Thanksgiving dinner she knows that a 20 pound turkey Is enough to feed 16 people at this

rate what size turkey will mrs. Wheeler need it 21 people are expected to come over for a dinner .

1 answer:

dalvyx [7]2 years ago

7 0

Basically it’s a proportionality...hope this helps :)

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Ann has bought 10 pounds of dog food. She feeds her dog

Yanka [14]

Answer:

25 meals

Step-by-step explanation:

She has 10 pounds total and she feeds 2/5 per meal, so we do 10/(2/5)) to get 25

Hope this helps

5 0

2 years ago

The price of an item has been reduced by 40%. The original price was $66. Find the price of the item now.

serious [3.7K]

Answer:

$39.60

Step-by-step explanation:

We are finding 66 - 40%

66 less 40% = 60% of 66

60% of 66 is the price of the item now.

Convert 60% to decimal form by dividing by 100.

60%/100 = 0.60

Multiply the decimal form by 66

66 X 0.6 = 39.60

Since we are dealing with money, keep 2 decimal places, even if the last digit is 0.

The price of the item now is $39.60.

7 0

3 years ago

N 1968, it cost $54,000 for a 30-second commercial during the Super Bowl. In 1973, the cost for a 30-second commercial was $88,0

madreJ [45]

In 5 years, the price increased about 30%.
I am not good at perentages, so correct me if I'm wrong. Also this is an estimation, not the exact percentage.

8 0

2 years ago

What is the 2nd equivalent fraction to <br> 1/11

alisha [4.7K]

2/22.
i think
sorry if it’s wrong

6 0

2 years ago

According to a report from the Center for Studying Health System Change, 20% of Americans delay or go without medical care becau

Svet_ta [14]

Answer:

The probability no one delays or goes without medical care is 0.168;

The probability only one person delays or goes without medical care is 0.336.

Step-by-step explanation:

This problem can be modeled with a binomial random variable, with sample size n=8 and probability of success p=0.2.

The probability that <em>exactly </em>k Americans delay or go without medical care because of concerns about cost within the sample of eight individuals can be calculated as:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{8}{k} 0.2^{k} 0.8^{8-k}\\\\\\$

The probability no one delays or goes without medical care (x=0) is:

$P(x=0) = \dbinom{8}{0} p^{0}(1-p)^{8}=1*1*0.168=0.168\\\\\\$

The probability only one person delays or goes without medical care (x=1) is

$P(x=1) = \dbinom{8}{1} p^{1}(1-p)^{7}=8*0.2*0.21=0.336\\\\\\$

4 0

2 years ago