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andrew11 [14]
3 years ago
9

Is an imaginary "line" from the Earth to the Moon a line, a ray, or a segment? and WHY?

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

Segment

Step-by-step explanation:

It is a segment because it has two endpoints (the Earth and Moon). If it was a ray, it would go on forever in one direction. It doesn't, so the imaginary line is a segment.  

The first image is a segment, the second is a ray.

Hope this helps. :)

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Solve <br> 4x+3y=-2<br> 3x + 5y = 15
ivann1987 [24]

Answer:

x=-5 y=6

Step-by-step explanation:

Multiply the first by 3 and the second by -4

Then add them. Y will be 6

Put 6 for y in the first one and youll find x=-5

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3 years ago
I know the right answer to this I just don't know how to get it, please help.
Pachacha [2.7K]
\bf \cfrac{x^2+5x+6}{x+4}\cdot \cfrac{x^2+x-12}{x^2+x-2}\implies \cfrac{\underline{(x+2)}(x+3)}{\underline{x+4}}\cdot \cfrac{\underline{(x+4)}(x-3)}{\underline{(x+2)}(x-1)}&#10;\\\\\\&#10;\cfrac{(x+3)(x-3)}{x-1}

and yes, the restrictions are -4, -2 and 1.

the original expression has such restrictions because if ever "x" becomes one of those values, one of the denominators will turn to 0 making the fraction undefined.
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3 years ago
What are the coordinates of the vertex for f(x) =3x^2+6x+3
Liono4ka [1.6K]
The x-coordinate of the vertex can be found by -b/2a where the equation is ax^2 + bx + c

3x^2 + 6x + 3

b is 6, and a is 3

-b/2a = -6/2(3) = -6/6 = -1

The x-coordinate of the vertex is -1. To find the y-coordinate plug the x-coordinate into the equation and solve for y.

f(-1) = 3(-1)^2 + 6(-1) + 3
= 3(1) - 6 + 3
= 3 - 6 + 3
= 0

The y-coordinate is 0

The vertex is (-1, 0)
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3 years ago
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Read 2 more answers
1. Sand falling from a chute forms a conical pile whose altitude is always equal to 4/3 the radius of the base. (a) How fast is
solong [7]

Answer:

The volume is increasing at a rate of 16286 in³/min.

Step-by-step explanation:

a) The volume of a cone is given by:

V = \frac{1}{3}h\pi r^{2}

Where:    

r: is the radius

h: is the height

The rate of change of the volume can be calculated by using the chain rule:

\frac{dV}{dt} = \frac{\pi}{3}[\frac{dh}{dt}r^{2} + h\frac{d(r^{2})}{dt}]

Since h = 4/3 r we have:

\frac{dV}{dt} = \frac{\pi}{3}[\frac{d(\frac{4r}{3})}{dt}r^{2} + \frac{4r}{3}\frac{d(r^{2})}{dt}]

\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + r\frac{d(r^{2})}{dt}]        

\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + 2r^{2}\frac{dr}{dt}]    (1)    

With:

\frac{dr}{dt} = 3 in/min

r = 3 ft*\frac{12 in}{1 ft} = 36 in

And by entering the above values into equation (1) we have:

\frac{dV}{dt} = \frac{4\pi}{9}[(3 in/min)*(36 in)^{2} + 2*(36 in)^{2}*3 in/min]

\frac{dV}{dt} = 16286 in^{3}/min

Therefore, the volume is increasing at a rate of 16286 in³/min.

I hope it helps you!                                    

3 0
3 years ago
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