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Pepsi [2]
3 years ago
14

What is the answer for 2-2

Mathematics
2 answers:
DochEvi [55]3 years ago
6 0

Answer:

0

Step-by-step explanation:

If you are subtracting 2 from 2 then it would be 0.

dybincka [34]3 years ago
6 0
if you put are subtracting it is 0
if you are multiplying it is 4 and if you divided it is 10
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I don’t get this please help me
8_murik_8 [283]
Answer: Brand B is

Explanation
(Brand A)24 diapers is 0.29¢ per diaper
(Brand B) 50 diapers is 0.27¢ per diaper
3 0
2 years ago
The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f
Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen  who carry a credit card balance.

The formula for the interval is:

p'₁±Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }

Z_{1-\alpha /2}= Z_{0.95}= 1.648

0.37±1.648*\sqrt{\frac{0.37*0.63}{1000} }

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂±Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }

0.48±1.648* \sqrt{\frac{0.48*0.52}{1000} }

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: \sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015

Seniors: \sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0
3 years ago
How can I write 0.4 in word form ?
Art [367]

Answer:

four tenths

Step-by-step explanation:

5 0
3 years ago
Eliott was trying to factor 6x^2-18 . He found that the greatest common factor of these terms was 6 and made an area model:
Semenov [28]

x²-3

Step-by-step explanation:

The expression given is;

6x²-18

Finding the greatest common factor of the terms and simplifying the expression will be;

Divide the terms by 6 to get;

x²-3

Graphing the expression to find the area model will be as attached;

Learn More

Factorizing expressions:brainly.com/question/12290978

Keywords : factor, greatest common factor, terms, area model

#LearnwithBrainly

4 0
3 years ago
How much ice cream can be put into a cone with radius 3.5 cm and height 12cm​
ivolga24 [154]

Step-by-step explanation:

radius of the cone = 3.5cm

height of cone = 12 cm

volume of cone = pie × r ^2 × h

= 1/3 × 22/7 × 35/10× 35 /10 × 12  = 154 cm^3

the extra icecream cannot be measured untill it's weight is not given.

6 0
3 years ago
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