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charle [14.2K]
3 years ago
7

What is ​ BC ​ ? Enter your answer in the box.

Mathematics
1 answer:
tangare [24]3 years ago
5 0
Lines AB and AC are equal so you set up an equation like so...
4x + 1 = 2x + 23
Subtract 1 from both sides.
4x = 2x + 22
Subtract 2x from both sides.
2x = 22
Divide.
x = 11
Now you need to plug in 11 into 3x - 8.
3(11) - 8
= 33 - 8
= 25
So BC is 25.
I hope this helps love! :) 
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Answer: Since you already know that the ordered pair is in the format of (x, y), then you can label one of the ordered pairs as 1 and kind of distribute it to get 1(x, y) = (x-sub1, y-sub1). Then just use the slope formula (y2-y1)/(x2-x1).

Step-by-step explanation:

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3 years ago
Which ordered pair is a solution to the system of linear equations 1/2x-3/4y=11/60 and 2/5x+1/6y=3/10
Leona [35]

Answer:

(\frac{2}{3} , \frac{1}{5})

Step-by-step explanation:

The fastest way to do this is to convert both equations into slope-intercept form and graph it to find the solution point. If you wanted to do this algebraically, you might want to start out by getting rid of the fractions and using either substitution or elimination to find x and y.

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The expression 2x + 50 represents the elevation above sea level, in meters, of a rock climber after x minutes of climbing. What
vova2212 [387]
We let y equal to the elevation above sea level so that the elevation of the rock climber after x minutes of climbing would be:

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3 years ago
(a) Find parametric equations for the line through (1, 4, 4) that is perpendicular to the plane x − y + 2z = 7. (Use the paramet
Alex777 [14]

Answer:

x=1+t\\y=4-t\\z=4+2t

Step-by-step explanation:

A vector perpendicular to the plane ax+by+cz+d=0 is of the form (a,b,c).

So, a vector perpendicular to the plane x − y + 2z = 7 is (1,-1,2).

The parametric equations of a line through the point (x_0,y_0,z_0) and parallel to the vector (a,b,c) are as follows:

x=x_0+at\\y=y_0+bt\\z=z_0+ct

Put (x_0,y_0,z_0)=(1,4,4) and (a,b,c)=(1,-1,2)

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xy-plane:

Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6

So, at point (-1,6,0)

yz-plane:

Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2

So, at point (0,5,2)

xz-plane:

Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12

So, at point (5,0,12)

5 0
3 years ago
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bearhunter [10]

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4 0
3 years ago
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