Question

Please answer my questions is really easy but idk

Answer 1

Given:

$m \angle A B D=96^{\circ}$

$m \angle 2 =m \angle 1+ 26^{\circ}$

To find:

$m \angle 1$

Solution:

$m \angle DBC+ m \angle CBA = m \angle ABD$

$m \angle 1+ m \angle 2 = m \angle ABD$

Substitute $m \angle 2 =m \angle 1+ 26^{\circ}$.

$m \angle 1+ m \angle 1 + 26^\circ = 96^\circ$

$2m \angle 1+ 26^\circ = 96^\circ$

Subtract 26° from both sides.

$2m \angle 1+ 26^\circ -26^\circ = 96^\circ -26^\circ$

$2m \angle 1 = 70^\circ$

Divide by 2 on both sides, we get

$m \angle 1=35^{\circ}$

Therefore, m∠1 = 35°.

Answer 2

Answer:

35°

Step-by-step explanation:

Let angle 1 be x

Angle 2: x + 26

x + x + 26 = 96

2x = 70

x = 35