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Bad White [126]
3 years ago
8

Hello! I graduated in 2008 but forgot how to solve multiplication. It's been so long. However I want to be refreshed on solving

44•12
Mathematics
1 answer:
Anettt [7]3 years ago
5 0
To do this you first have to set this up vertically.
First you multiply through with the 2 (44×2=88). Then next, you have to multiply through with the 1 (44×1=44) But since this is the second line, you have to add the 0 to the end (440).
Now you simply add 88+440=528.
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The Strikers soccer team has 20 members, and 8 of them play offense. What percent of the team members play offense?
bulgar [2K]

Answer:

40%

Step-by-step explanation:

We already have our first value 20 and the second value 8. Let's assume the unknown value is Y which answer we will find out.

As we have all the required values we need, Now we can put them in a simple mathematical formula as below:

Step 1 ⇒ Y = 8/20

By multiplying both numerator and denominator by 100 we will get:

Step 2 ⇒ Y = 8/20 × 100/100 = 40/100

Step 3 ⇒ Y = 40

Finally, we have found the value of Y which is 40 and that is our answer.

3 0
3 years ago
Which is the correct label of the parallel lines
Tpy6a [65]
The symbol to show that there are parallel lines is normally just a set of vertical lines. Although if these are being drawn on a page and need to be labelled as part of a shape or diagram, sometimes arrows will be used to show they are parallel - either one arrow in the middle of the line, or two arrows to show they are parallel but in different directions.
8 0
3 years ago
Read 2 more answers
Who do I explain how I got the answer?
ratelena [41]
You list every step that you did with full sentences and why you did each step
7 0
3 years ago
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
marin [14]

If you do in fact mean f(1)=f(6)=0 (as opposed to one of these being the derivative of f at some point), then integrating twice gives

f''(x) = -\dfrac1{x^2}

f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1

f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2

From the initial conditions, we find

f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0

f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)

Eliminating C_2, we get

(C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))

-5C_1 = \ln(6)

C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)

Then

\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}

3 0
2 years ago
The sum of 15 and two times a number is 29 what is the number?
vodka [1.7K]

Let the number = x

It would be: 15+2x = 29

2x = 14

x=7

4 0
4 years ago
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