Integration will be ln | ( x /9 ) + (
) | + c .
Given ∫ 1 dx / (
- 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / (
- 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + (
/ 9 ) | + c
= ln | ( x /9 ) + (
) | + c
Hence , the integration will be ln | ( x /9 ) + (
) | + c .
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<h2>
Answer with explanation:</h2>
In statistics, The Type II error occurs when the null hypothesis is false, but fails to be rejected.
Given : Suppose the null hypothesis,
, is: Darrell has enough money in his bank account to purchase a new television.
Then , Type II error in this scenario will be when the null hypothesis is false, but fails to be rejected.
i.e. Darrell has not enough money in his bank account to purchase a new television but fails to be rejected.
You have to multiply 3 times 2= 6 + 4 = 10 so the answer is 10 I hope this help...
Answer:
0.14
0.29
0.21
0.27
18.38
0.83
Step-by-step explanation:
So since this is half a circle, we have to divide the area of a circle by 2. So that would give us 1/2 pi* r^2. We find the radius by dividing 10 by 2. So the radius is 5. Plugging that in for r in 1/2(pi)(r^2) we get 1/2(pi)(5^2) which is 25pi/2. Turning pi into 3.14 we have (25(3.14))/2 which is 78.5/2 which is approximately 39.25 units^2