Question

6

Answer 1

Answer:

A'(0,2), B(1, -2). C'(3,2)

Step-by-step explanation:

Given

$A = (-4,-1)$

$B = (-3,-5)$

$C =(-1,-1)$

Solving (a); Graph and Label ABC

See attachment for graph

Solving (b): Graph and Label A'B'C'

Translation:

4 units right

3 units up

4 units right

The rule is:

$(x,y) \to (x + 4,y)$

So, we have:

$A = (-4,-1)$ ==> $(-4+4,-1) =(0,-1)$

$B = (-3,-5)$ ==> $(-3+4,-5) =(1,-5)$

$C =(-1,-1)$ ==> $(-1+4,-1) =(3,-1)$

3 units up

The rule is:

$(x,y) \to (x,y+3)$

So, we have:

$(0,-1)$ ==> $A' =(0,-1+3) = (0,2)$

$(1,-5)$ ==> $B' =(1,-5+3) = (1,-2)$

$(3,-1)$ ==> $C' =(3,-1+3) = (3,2)$

The coordinates of A' B' and C' are:

A'(0,2), B(1, -2). C'(3,2)

See attachment for graph