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Alik [6]
3 years ago
8

Which cloud is found ahead of a cold front, but behind the warm front?

Biology
1 answer:
Nataliya [291]3 years ago
6 0

Answer:

I believe it's cirrus clouds.

Explanation:

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Which of the following best describes a characteristics that differentiates animalia and plantae ?
Kisachek [45]
Animalia are heterotrophs while plantae are autotrophs
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OC (5) How do you know that the gas produced during fermentation is carbon dioxide (2)​
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Explanation:

everything can be found in the picture

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Your patient has a hematocrit of 56%. You recall from your anatomy and physiology class that high hematocrits are often a sign o
marissa [1.9K]

Answer:

Dehydration from flu

Explanation:

On centrifugation, blood forms different regions plasma region, the Buffy coat and the hematocrit which contains the erythrocytes or the red blood cells.

The normal range is between 37-52 percent of the total whole blood.

Any value below shows anemia and any value above indicates polycythemia.

Polycythemia is usually a sign of doping in athletes however for this elderly patient. It must have been caused due to dehydration from the flu.

8 0
3 years ago
A company discovers a coal reserve under a mountain. The company uses bulldozers to remove soil and flatten the top of the mount
RSB [31]

Answer:

The removal of soil will increase the rate of erosion and the flattening of the mountain will change the direction in which water flows off of the mountain.

3 0
3 years ago
LION
Bess [88]

The frequencies of R is 0.75 and the frequencies for R' is 0.25.

Explanation:

Data given:

Genotype frequency of incomplete dominance on flower colour of snapdragon:

RR = red 0.5625

RR' = Pink 0.375

R'R' = 0.0625

frequency of R and R'=?

According to Hardy-Weinberg equilibrium the genetic variation in  a given population is constant from one generation to other if no factors causing evolution or genetic drift is there. So,

p^{2} + q^{2}+ 2pq = 1

The p represents = homozygous dominant  RR

q represents = homozygous recessive   R'R'

2pq = frequency of heterpzygous genotype RR'

p^{2} = 0.5625

p = 0.75   (frequency of R)

q^{2} = 0.0625

q = 0.25  (Frequency of R')

Their sum is 1 as according to Hardy Weinberg condition:

p+q = 1

6 0
3 years ago
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