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ikadub [295]
3 years ago
9

Amaya is painting a fence that is 4 1/2 meters long.She painted 3/4 of the fence before stopping for lunch.How many meters of th

e fence did Amaya paint before lunch?
Mathematics
2 answers:
Naily [24]3 years ago
8 0

Answer:

3 3/8 meters.

Step-by-step explanation:

4 1/2 * 3/4

= 9/2 * 3/4

= 27/8

= 3 3/8 meters.

Zina [86]3 years ago
7 0

Answer: She painted 3.375 meters before lunch.

Step-by-step explanation:  

4.5x.75=3.375

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256 lieh

Step-by-step explanation:

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An alloy is composed of nickel, zinc, and copper in a ration of 7:2:9. How many kilograms of each metal are needed to make 3.6kg
motikmotik
Well, the short answer is, we divide that 3.6 by (7+2+9) and then we give as many pieces at the ratio to each, so let's do so,

\bf \stackrel{nickel}{7}~~:~~\stackrel{zinc}{2}~~:~~\stackrel{copper}{9}
\\\\\\
\stackrel{nickel}{7\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{zinc}{2\cdot \frac{3.6}{7+2+9}}~~:~~\stackrel{copper}{9\cdot \frac{3.6}{7+2+9}}
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\stackrel{nickel}{7\cdot 0.2}~~:~~\stackrel{zinc}{2\cdot 0.2}~~:~~\stackrel{copper}{9\cdot 0.2}
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\stackrel{nickel}{1.4}~~:~~\stackrel{zinc}{0.4}~~:~~\stackrel{copper}{1.8}
6 0
3 years ago
Read 2 more answers
Which angle is an obtuse angle?<br> A. 310°<br> B. 80°<br> O c. 260°<br> O D. 170°
Murljashka [212]

Step-by-step explanation:

obtuse angle is an angle whose measure is more than 90 degree but less than 180 degree..

So,

170°

3 0
3 years ago
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Why is deferment an important aspect of student loans? a. Most students are unable to make monthly payments while studying, so d
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6 0
4 years ago
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MATH HELP PLZ!!!
RoseWind [281]

Answer:

a)    tan (157.5) = \frac{1-cos 315}{sin315}

b)

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c)

      sin^{2} (157.5) = \frac{1-cos (315) }{2}

d)

  cos 330° = 1- 2 sin² (165°)

       

         

Step-by-step explanation:

<u><em>Step(i):-</em></u>

By using trigonometry formulas

a)

cos2∝  = 2 cos² ∝-1

cos∝ = 2 cos² ∝/2 -1

1+ cos∝ =  2 cos² ∝/2

cos^{2} (\frac{\alpha }{2}) = \frac{1+cos\alpha }{2}

b)

cos2∝  = 1- 2 sin² ∝

cos∝  = 1- 2 sin² ∝/2

sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

<u><em>Step(i):-</em></u>

Given

              tan\alpha = \frac{sin\alpha }{cos\alpha }

          we know that trigonometry formulas

        sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

         1- cos∝ =  2 sin² ∝/2

      Given

         tan(\frac{\alpha }{2} ) = \frac{sin(\frac{\alpha }{2} )}{cos(\frac{\alpha }{2}) }

put ∝ = 315

      tan(\frac{315}{2} ) = \frac{sin(\frac{315 }{2} )}{cos(\frac{315 }{2}) }

     multiply with ' 2 sin (∝/2) both numerator and denominator

        tan (\frac{315}{2} )= \frac{2sin^{2}(\frac{315)}{2}  }{2sin(\frac{315}{2} cos(\frac{315}{2}) }

Apply formulas

 sin\alpha = 2sin(\frac{\alpha }{2} )cos(\frac{\alpha }{2} )

  1- cos∝ =  2 sin² ∝/2

now we get

 tan (157.5) = \frac{1-cos 315}{sin315}

       

b)

          sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 330° above formula

             sin^{2} (\frac{330 }{2}) = \frac{1-cos (330) }{2}

            sin^{2} (165) = \frac{1-cos (330) }{2}

            sin (165) =\sqrt{ \frac{1-cos (330) }{2}}

c )

         sin^{2} (\frac{\alpha }{2}) = \frac{1-cos\alpha }{2}

               put ∝ = 315° above formula

             sin^{2} (\frac{315 }{2}) = \frac{1-cos (315) }{2}

            sin^{2} (157.5) = \frac{1-cos (315) }{2}

           

d)

     cos∝  = 1- 2 sin² ∝/2

   put      ∝ = 330°

       cos 330 = 1 - 2sin^{2} (\frac{330}{2} )

      cos 330° = 1- 2 sin² (165°)

3 0
3 years ago
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