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Arada [10]
3 years ago
10

Using the example above as a guide, fill in the missing information. Enter percentage answers to the nearest tenth.

Mathematics
2 answers:
SashulF [63]3 years ago
5 0

Solution: We know that height of trees follows a normal distribution with mean height \mu=60 inches and standard deviation \sigma =12 inches

Now let's fill the missing values as per the normal distribution and the given information.

a0=34.1\% of 500 = 0.341 \times 500

           =170.5 \approx 171

Now, let's find the value of a1. Since the height follows normal distribution with mean 60 and standard deviation = 12. Therefore, we have:

a1=\mu+\sigma = 60+12=72

To find the value of a2, we need to use the empirical rule of normal distribution. According to empirical rule, the area between Mean and 1 standard deviation above mean is 34.1%. Therefore, the value of a2 is:

a2=34.1\%

a3 denotes the area between +1 and +2 (72 to 84 inches). According to empirical rule of normal distribution, the area between one standard deviation above mean and two standard deviation mean is 13.6%.

\therefore a3=13.6\%

And a4=13.6\% of 500=0.136 \times 500=68

Therefore, the complete table is attached here.


IRISSAK [1]3 years ago
3 0

Answer:

72

34

13.6

171

68


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equation for the sum of three consecutive even integers is 48 less than twice the smallest of the three integers
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2x - the first and the smallest even integer
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2x=-54 \\ \\
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If f(x) = x2 − 1, and f(2a) = 35, then what could be the value of a ?
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4 years ago
Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 9
Tomtit [17]

Answer:

34.01% probability that his score is at least 532.1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 493, \sigma = 95

If 1 of the men is randomly selected, find the probability that his score is at least 532.1.

This is 1 subtracted by the pvalue of Z when X = 532.1. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{532.1 - 493}{95}

Z = 0.41

Z = 0.41 has a pvalue of 0.6591

1 - 0.6591 = 0.3409

34.01% probability that his score is at least 532.1.

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3 years ago
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