3 years ago

What IS the distance between the points (7, 8) and (-8, 0) on a coordinate grid?

Mathematics

1 answer:

amid [387]3 years ago

8 0

Answer:

Step-by-step explanation:

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The measures of the angles of △ABC are given by the expressions in the table.

antoniya [11.8K]

Answer:

First You add all given angles up to equal 180 to give you x then you plug x into equations

Step-by-step explanation:

A= 125 degrees

C= 35 degrees

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3 years ago

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What is the slip of the line shown below ? A - 11/4 B- 4/11 C- -4/11 D- 11/4

RUDIKE [14]

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Akira and a business associate agree to invest in a project estimated to cost $1.8 million (1,800,000). They decide to split the

MariettaO [177]

If it's relationship Akira : Business A. = 7:5

The part of Akira is 7k

and the part of the Business A. is 5k

Then

7k+5k=12k => 12k=1,800,000 => k= 1,800,00/12=150,000$

Akira part is 7k= 7 * 150,000 = 1,050,000$

Good luck!!!!

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3 years ago

A is the midpoint (3,6) and B is the midpoint (11,12).find the coordinates of midpoint of AB

tamaranim1 [39]

Answer:

X, y first column ++

Second column +-

Fourth column - -

Fiveth column _+

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4 years ago

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How to solve: <img src="https://tex.z-dn.net/?f=log_%7B3%7D%20%28x%2B6%29%20%2B%20log_%7B3%7D%28x-6%29%20%3D%204" id="TexFormula

Shalnov [3]

Collapse the logarithms into one:

$\log_3(x+6)+\log_3(x-6)=\log_3((x+6)(x-6))=4$

Then write both sides as powers of 3:

$3^{\log_3((x+6)(x-6))}=3^4$

$(x+6)(x-6)=81$

Simplify the left side and solve for $x$ :

$x^2-36=81$

$x^2=117$

$x=\pm\sqrt{117}=\pm3\sqrt{13}$

But we're not done yet. Notice that both $x+6$ and $x-6$ are negative when $x=-3\sqrt{13}$ . We can't take the logarithm of a negative number (the result isn't real-valued, anyway), so we throw this solution out, and we're left with just

$x=3\sqrt{13}$

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3 years ago