<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>
<em><u>Solution:</u></em>
Given that,
<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>
<em><u>At what times will the object be at a height of 56 feet</u></em>
<em><u>Substitute h = 56</u></em>
Solve the above equation by quadratic formula
Thus, at 2 second and 1.75 second, the object be at a height of 56 feet
The equation of a line that passes through (x1,y1) and has a slope of m is
y-y1=m(x-x1)
find slope
slope between (x1,y1) and (x2,y2) is
(y2-y1)/(x2-x1)
given
(-3,2) and (2,1)
slope=(1-2)/(2-(-3))=(-1)/(2+5)=-1/5
pikc a point
if we pick (-3,2)
(x1,y1)
x1=-3
y1=2
y-2=-1/5(x-(-3))
y-2=-1/5(x+3)
that is D
I only know the answer for b I don't know the answer for d. So here is the answer for b 9 time 9= to 18+11+8x4-1=60
Answer:Each Y could equal 12
Step-by-step explanation:
You would divide each side of the equation y 3 to get y^2=144.
Next take the root of both sides to get y= ± 12
After that just separate the solutions and get 12.
(I hope this helps. I tried)
<span>y = 4x^2 - 8x + 6 = (2x - 2)^2 + 2 = 4(x - 1)^2 + 2</span><span>
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