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e-lub [12.9K]
3 years ago
14

Please help! find QPR

Mathematics
1 answer:
aleksley [76]3 years ago
7 0

Answer:

m∡QPR = 25°

Step-by-step explanation:

solve for 'x':

8x + 7 + 9x + 16 = 40

17x + 23 = 40

17x = 17

x = 1

m∡QPR = 9(1) + 16

m∡QPR = 25°

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A 3 foot wide brick sidewalk is laid around a rectangular swimming pool. The outside edge of the sidewalk measures 30 feet by 40
ipn [44]

Answer with Step-by-step explanation:

A 3 foot wide brick sidewalk is laid around a rectangular swimming pool.

The outside edge of the sidewalk measures 30 feet by 40 feet.

Length of swimming pool=(30-3-3) feet

                                          =24 feet

Breath of swimming pool=(40-3-3) feet

                                         = 34 feet

Perimeter of swimming pool=2(24+34) feet

(since perimeter of rectangle=2(l+b) where l is the length and b is the breath of the rectangle)

Perimeter of swimming pool=116 feet

Hence, Perimeter of swimming pool is:

116 feet

7 0
3 years ago
Tyler's family has 4 children. How many ways can they line up to get their flu shot at the doctor?
Andrews [41]

Answer:

16 if im correct

Step-by-step explanation:

4x4=16.

aaaaaa im sorry i did not know that I did not know this :C ill try

6 0
3 years ago
Calculus hw, need help asap with steps.
nikdorinn [45]

Answers are in bold

S1 = 1

S2 = 0.5

S3 = 0.6667

S4 = 0.625

S5 = 0.6333

=========================================================

Explanation:

Let f(n) = \frac{(-1)^{n+1}}{n!}

The summation given to us represents the following

\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=\sum_{n=1}^{\infty} f(n)\\\\\\\displaystyle \sum_{n=1}^{\infty} \frac{(-1)^{n+1}}{n!}=f(1) + f(2)+f(3)+\ldots\\\\

There are infinitely many terms to be added.

-------------------

The partial sums only care about adding a finite amount of terms.

The partial sum S_1 is the sum of the first term and nothing else. Technically it's not really a sum because it doesn't have any other thing to add to. So we simply say S_1 = f(1) = 1

I'm skipping the steps to compute f(1) since you already have done so.

-------------------

The second partial sum is when things get a bit more interesting.

We add the first two terms.

S_2 = f(1)+f(2)\\\\S_2 = 1+(-\frac{1}{2})\\\\S_2 = \frac{1}{2}\\\\S_2 = 0.5\\\\\\

The scratch work for computing f(2) is shown in the diagram below.

-------------------

We do the same type of steps for the third partial sum.

S_3 = f(1)+f(2)+f(3)\\\\S_3 = 1+(-\frac{1}{2})+\frac{1}{6}\\\\S_3 = \frac{2}{3}\\\\S_3 \approx 0.6667\\\\\\

The scratch work for computing f(3) is shown in the diagram below.

-------------------

Now add the first four terms to get the fourth partial sum.

S_4 = f(1)+f(2)+f(3)+f(4)\\\\S_4 = 1+(-\frac{1}{2})+\frac{1}{6}-\frac{1}{24}\\\\S_4 = \frac{5}{8}\\\\S_4 \approx 0.625\\\\\\

As before, the scratch work for f(4) is shown below.

I'm sure you can notice by now, but the partial sums are recursive. Each new partial sum builds upon what is already added up so far.

This means something like S_3 = S_2 + f(3) and S_4 = S_3 + f(4)

In general, S_{n+1} = S_{n} + f(n+1) so you don't have to add up all the first n terms. Simply add the last term to the previous partial sum.

-------------------

Let's use that recursive trick to find S_5

S_5 = [f(1)+f(2)+f(3)+f(4)]+f(5)\\\\S_5 = S_4 + f(5)\\\\S_5 = \frac{5}{8} + \frac{1}{120}\\\\S_5 = \frac{19}{30}\\\\S_5 \approx 0.6333

The scratch work for f(5) is shown below.

7 0
2 years ago
A dice is rolled 2 times. What is the probability of showing a 5 on every roll Round to 4 decimal places
AlexFokin [52]

Answer:

0.0278

Step-by-step explanation:

(1/6)(1/6) = 1/36 = 0.0278

3 0
3 years ago
Compare -4 ____ -12 9 ___ -35
omeli [17]
-4 < -12 and 9 > -35

Hope this helps!
5 0
3 years ago
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