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3 years ago

Find the surface area of the prism. 5cm 7cm 4cm

Mathematics

1 answer:

Georgia [21]3 years ago

4 0

To find the volume it is Length x Width x Height
so 7 x 5 x 4 = 140cm
140 cm is the answer
Hoped this helped =)

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If Richard can paint their living room in 4 hours, and Vanessa can paint the same living room in 5 hours, then how long will it

Tju [1.3M]

Answer:

2 hrs 13 mins

Step-by-step explanation:

If Richard can paint the living room in 4 hrs, then in 1 hour he can paint 1/4 of the living .

If Vanessa can paint the living room in 5 hours, then in one hour, she can paint 1/5 of the living room.

In one hour Richard and Vanessa can paint 1/4 + 1/5 = 1/y

y is the number of hours it will take both Richard and Vanessa to paint the living room. 1/y is how much of the house they can paint in one hour.

1/4 + 1/5 = 1/y

(5 + 4)/20. ( find the LCM)

9/20 = 1/y

9y= 20

y = 20/9

y = 2.22hrs

y = 2 hrs 13 mins

4 0

4 years ago

The calibration of a scale is to be checked by weighing a 13 kg test specimen 25 times. Suppose that the results of different we

Natali5045456 [20]

Solution :

a).

Given : Number of times, n = 25

Sigma, σ = 0.200 kg

Weight, μ = 13 kg

Therefore the hypothesis should be tested are :

$H_0 : \mu = 13$

$H_a : \mu \neq 13$

b). When the value of $\overline x = 12.84$

Test statics :

$Z=\frac{(\overline x - \mu)}{\frac{\sigma}{\sqrt n}}$

$Z=\frac{(14.82-13)}{\frac{0.2}{\sqrt {25}}}$

$=\frac{1.82}{0.04}$

= 45.5

P-value = 2 x P(Z > 45.5)

= 2 x 1 -P (Z < 45.5) = 0

Reject the null hypothesis if P value < α = 0.01 level of significance.

So reject the null hypothesis.

Therefore, we conclude that the true mean measured weight differs from 13 kg.

3 0

3 years ago

SOLVE FOR J. <br><br> j+11.98≥-7.02 <br> (that is not a subtraction sign its a negative sign!!)

LiRa [457]

J>-19

Hope that helps

7 0

3 years ago

Which expression is equivalent to the following complex fraction?

Sedbober [7]

Answer:

$\dfrac{2(y-2x)}{3y-5x}$

Step-by-step explanation:

When you simplify the numerator and the denominator, you find they both have denominators of xy. So, the ratio of those is the ratio of their numerators.

$\dfrac{\dfrac{2}{x}-\dfrac{4}{y}}{\dfrac{-5}{y}+\dfrac{3}{x}}=\dfrac{\left(\dfrac{2y-4x}{xy}\right)}{\left(\dfrac{-5x+3y}{xy}\right)}=\dfrac{2y-4x}{-5x+3y}\\\\=\boxed{\dfrac{2(y-2x)}{3y-5x}}$