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Given:
In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.
To find:
The equation for the given situation if the sum of the numbers is 77.
Solution:
a. Let the first number in the set is x.
The second is 3 more than the first. So, the second number is .
The 3rd number is a square of the second. So, the third number is .
Therefore, the first, second and third numbers are respectively.
b. The sum of the numbers is 77.
First number + Second number + Third number = 77
c. So, the equation in terms of x is:
Therefore, the required equation is .
d. On simplification, we get
Subtract 77 from both sides.
Therefore, the simplified form of the required equation is .