She would have $350 dollars left.
Answer: 332640 anagrams
Step-by-step explanation:
Given the word:
'masslessness'
Total number of letters= 12
Number of S = 6
E =2
The rest are one each.
The number of possible arrangements can be written as;
N = 12!/(6!2!)
N = 332640
Fred's age is 13 years
Let
Fred's age = x
Jack's age = 2x + 4
After 8 years:
- Fred's age = x + 8
- Jack's age = 2x + 4 + 8
= 2x + 12
Sum of their ages = Fred's age + Jack's age
59 = (x + 8) + (2x + 12)
59 = x + 8 + 2x + 12
59 = 3x + 20
59 - 20 = 3x
39 = 3x
x = 39/3
x = 13 years
Therefore, Fred's age = 13 years
brainly.com/question/24371832
<span>This question is to find the algebraic expression given by words. Call the unknown number x. Then the sum of it and eight is x + 8. Two sets of it means 2 (x + 8). Now that added to five times the number is 2 (x + 8) + 5x. Then, the answer is: 2 (x + 8) + 5x. </span>
Answer:
9) 1/42
10) 1/14
Step-by-step explanation:
The probability of the compound event is the product of the probabilities of the parts. Note that the first draw (without replacement) modifies the probability of associated with the second draw.
<h3>9.</h3>
5 is one of 7 tiles. After drawing 5, 6 is one of 6 tiles.
P(5 then 6) = P(5) × P(6 | 5) = 1/7 × 1/6 = 1/42
<h3>10.</h3>
There are 3 odd tiles among the 7. After drawing one of them, 20 is one of 6 tiles.
P(odd then 20) = P(odd) × P(20 | odd) = 3/7 × 1/6 = 3/42 = 1/14
_____
Alternatively, you can consider the number of permutations of 2 tiles out of 7. That is P(7, 2) = 7!/(7-2)! = 7·6 = 42. Then the trick is to count how many of them will be the sequence of interest.
5 then 6: Among the 42 ways 2 tiles can be drawn, there is only one that is the required sequence: P(5,6) = 1/42.
odd then 20: There are 3 odd numbers, so the possible sequences of interest are (5,20), (7,20), (9,20). That is, there are 3 of 42 sequential draws that match the criteria. P(odd,20) = 3/42 = 1/14.
