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Keith_Richards [23]
3 years ago
6

How many anagrams can be created from the word 'masslessness' if the new words do not need to be meaningful?

Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer: 332640 anagrams

Step-by-step explanation:

Given the word:

'masslessness'

Total number of letters= 12

Number of S = 6

E =2

The rest are one each.

The number of possible arrangements can be written as;

N = 12!/(6!2!)

N = 332640

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Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

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In this case,

                                n  = 2, r=1.

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In this case,

                                n  = 20, r=10.

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                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

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In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

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