In python 3.8:
def func(value_list):
lst = [x for x in value_list if type(x) == int or type(x) == float]
return sum(lst)
print(func(["h", "w", 32, 342.23, 'j']))
This is one solution using list comprehensions. I prefer this route because the code is concise.
def func(value_list):
total = 0
for x in value_list:
if type(x) == int or type(x) == float:
total += x
return total
print(func(["h", "w", 32, 342.23, 'j']))
This is the way as described in your problem.
Answer 515be559d883f8eab00011e5
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Answer:
The benefits of relying on System Development Standards is explained below.
Explanation:
There are many benefits of having a Well Defined Systems Development. It helps in having a pre - planned and well defined structure before the project starts. It helps in having a Clear view of the whole project and also each phase of the whole System Development. It helps in having an understanding of cost required and the revenues generated at each phase of the whole system development. It helps in having an understanding of the goal of each phase and procedures need to be followed for that particular goal. It also helps in having the quality checked and the improvements need to be made for the desired quality.
Answer:
The code to this question can be given as:
Code:
int lastVector = newScores.size() -1; //define variable lastVector that holds updated size of newScores.
newScores = oldScores; //holds value.
for (i = 0; i < SCORES_SIZE - 1; i++) //define loop.
{
newScores.at(i) = newScores.at(i+1); //holds value in newScores.
}
newScores.at(lastVector) = oldScores.at(0); //moving first element in last.
Explanation:
- In the given C++ program there are two vector array is defined that are "oldScores and newScores". The oldScores array holds elements that are "10, 20, 30, 40".
- In the above code, we remove the array element at first position and add it to the last position. To this process, an integer variable "lastVector" is defined.
- This variable holds the size of the newScores variable and uses and assigns all vector array elements from oldScores to newScores. In the loop, we use the at function the removes element form first position and add in the last position.
- Then we use another for loop for print newScores array elements.