If you want the answer in point slope form then,
y-y1 = m(x-x1)
y-c = m(x-a)
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If you want the answer in slope intercept form, then solve for y
y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)
For this answer in slope intercept form the slope is m and the y intercept is c-ma
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If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.
y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma
Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.
2m⁴ - 18n⁶
2(m⁴) - 2(9n⁶)
2(m⁴ - 9n⁶)
2(m⁴ - 3m²n³ + 3m²n³ - 9n⁶)
2[m²(m²) - m²(3n³) + 3n³(m²) - 3n³(3n³)]
2[m²(m² - 3n³) + 3n³(m² - 3n³)]
2(m² + 3n³)(m² - 3n³)
Answer:
$720
Step-by-step explanation:
First tutor = 30 x 10 = $300
Second tutor = 30 x 14 = $420
Total = 420 + 300 = $720
Step-by-step explanation:
the formula for the area of a sector is
(x°(r^2)π)/360
with x being the angle
r bring the radius of the circle
(255(13.4)^2π)/360
399.6
Hope that helps :)
You might have made an error the first time you solved for x. I got x = -0.5.
When you have your log base 4, the way you cancel that out is by making 4 the base on both sides, so you get 4^(log4) to reduce to 1, and you're left with:
2x + 3 = 4^(1/2) ... Simplify
2x + 3 = 2
2x = -1
x = -1/2
If you plug that back in, everything checks out. Maybe double check your use of logarithm/exponent properties?
