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liubo4ka [24]
3 years ago
13

A network engineer is troubleshooting a newly deployed wireless network that is using the latest 802.11 standards. When users ac

cess high bandwidth services such as streaming video, the wireless network performance is poor. To improve performance the network engineer decides to configure a 5 Ghz frequency band SSID and train users to use that SSID for streaming media services. Why might this solution improve the wireless network performance for that type of service
Computers and Technology
1 answer:
Lerok [7]3 years ago
5 0

Answer:

it will make the wireless network faster and it is a performance network i am pretty sure.

Explanation:

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To drive defensively, you should _______________.
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What additional uses of technology can you see in the workplace? List ways technology impacts
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Write a program that calculates the future value of an investment at a given interest rate for a specified number of years. The
baherus [9]
<h2>Question:</h2>

Write a program that calculates the future value of an investment at a given interest rate for a specified number of years. The formula for the calculation is as follows:

futureValue = investmentAmount * (1 + monthlyInterestRate) ^ years * 12

Note: Allow users to enter the values of the investmentAmount, monthlyInterestRate and years from standard input.

Assume the number of years is always a whole number.

<h2>Answer:</h2>

===================================================

//import the Scanner class

import java.util.Scanner;

//Class header definition

public class FutureValue{

   

    //Main method definition

    public static void main(String []args){

       

       //Create an object of the Scanner class

       Scanner input = new Scanner(System.in);

       

       //Prompt the user to enter the investment amount

       System.out.println("Enter the investment amount");

       

       //Store the input in a double variable called investmentAmount

       double investmentAmount = input.nextDouble();

       

       //Next, prompt the user to enter the interest rate

       System.out.println("Enter the interest rate in percentage");

       

       //Store the input in a double variable called interestRate

       double interestRate = input.nextDouble();

       

       //Convert the interest rate to decimal by multiplying by 0.01

       interestRate *= 0.01;

       

       //Convert the interest rate to monthly interest rate by dividing the

       //result above by 12

       double monthlyInterestRate = interestRate / 12;

       

       //Prompt the user to enter the number of years

       System.out.println("Enter the number of years");

       

       //Store the input in an integer variable called years

       int years = input.nextInt();

       

       //Using the given formula, find the future value

      double futureValue =  investmentAmount * Math.pow(1 + monthlyInterestRate, years * 12);

       

       //Print out the future value

      System.out.println("Future value : " + futureValue);

       

    } //End of main method

     

}  // End of class definition

===================================================

<h2>Sample Output</h2>

===================================================

<em>>> Enter the investment amount </em>

1000

>> <em>Enter the interest rate in percentage </em>

10

>> <em>Enter the number of years </em>

5

Future value : 1645.3089347785854

===================================================

<h2>Explanation:</h2>

The code above has been written using Java. The code contains comments explaining every line of the code. Please go through the comments. The actual lines of code have been written in bold-face to distinguish them from comments. A sample output has also been provided as a result of a run of the code.

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Read 2 more answers
A thermogram taken outside a house shows high amounts of thermal energy around the windows but not around the roof. which conclu
mestny [16]

The conclusion sustains the thermogram will be that the windows are not energy efficient, but the roof stands energy efficient.

<h3>What is Thermography?</h3>

Thermography exists a noninvasive method that employs an infrared camera to develop pictures that depict patterns of heat and blood flow on or around the body's surface. A thermogram taken outside a house shows high quantities of thermal energy around the windows but not around the roof. The conclusion that supports the thermogram will be that the windows are not energy efficient, but the roof exists energy efficient.

Thermal energy (also named heat energy) is produced when a rise in temperature pushes atoms and molecules to move faster and collide with each other. The energy that reaches the temperature of the heated substance is named thermal energy. The term "thermal energy" exists utilized loosely in various contexts in physics and engineering. It can guide several different well-defined physical concepts.

To learn more about Thermography refer to:

brainly.com/question/1500896

#SPJ4

The complete question is,

A thermogram taken outside a house shows high amounts of thermal energy around the windows but not around the roof.

Which conclusion supports the thermogram?

The windows and the roof are energy efficient.

The windows and the roof are not energy efficient.

The windows are not energy efficient, but the roof is energy efficient.

The windows are energy efficient, but the roof is not energy efficient.

4 0
1 year ago
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