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Alexandra [31]
4 years ago
5

Which network type connects each computer and device to a central device?

Computers and Technology
1 answer:
yulyashka [42]4 years ago
6 0
Answer: a Star NetNetwork Topology
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Which is a requirement for searching for a template
Lina20 [59]

Answer:

umm... you did not discribe the anwsers, i cannot help you

8 0
3 years ago
What are the inputs that the model uses to make decisions?
hodyreva [135]

Answer:

It makes the decision better and adds ownership in the implementation

Explanation:

Hope this helps C:

~Chiena

8 0
2 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
Write a program that asks the user to input an integer named numDoubles. Create a dynamic array that can store numDoubles double
Hitman42 [59]

Answer:

Answered in C++

#include <iostream>

using namespace std;

int main() {

   int size;

   cout<<"Length of array: ";

   cin >> size;

   double *numDoubles = new double[size];

   double sum =0;

   cout<<"Array Elements: ";

   for(int i=0;i<size;i++){

       cin>>numDoubles[i];

       sum += numDoubles[i];

   }

   delete [] numDoubles;

   cout<<"Average: "<<sum/size;

   return 0;  

}

Explanation:

This line declares the size (or length) of the array

<em>    int size; </em>

This line prompts the user for the array length

<em>    cout<<"Length of array: "; </em>

This gets the input from the user

<em>    cin >> size; </em>

This dynamically declares the array as of double datatype

<em>    double *numDoubles = new double[size]; </em>

This declares and initializes sum to 0

<em>    double sum =0; </em>

This prompts the user for elements of the array

<em>    cout<<"Array Elements: "; </em>

The following iteration gets input from the user and also calculates the sum of the array elements

<em>    for(int i=0;i<size;i++){ </em>

<em>        cin>>numDoubles[i]; </em>

<em>        sum += numDoubles[i]; </em>

<em>    } </em>

This deletes the array

<em>    delete [] myarray; </em>

This calculates and prints the average of the array

<em>    cout<<"Average: "<<sum/size; </em>

6 0
3 years ago
What can multivariable calculus show for a data set.
dalvyx [7]

Answer:

They can help to explain the relationship between the output and input variables.

Hope this Helps!

5 0
3 years ago
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