Note that Range = Max – Min.
In this case, Max = 452452, Min = 221221.
Hence, Range = 452452 – 221221 = 228230.
Sample Variance:
where n = 4,
Hence
![s^2= \frac{1}{4-1}[( 419419 - 374374)^2 + (452452-374374)^2+\\ (404404-374374)^2+ (221221-374374)^2)]\\ = 1.0828 \times 10^{10} ](https://tex.z-dn.net/?f=%20s%5E2%3D%20%5Cfrac%7B1%7D%7B4-1%7D%5B%28%20419419%20-%20374374%29%5E2%20%2B%20%28452452-374374%29%5E2%2B%5C%5C%0A%28404404-374374%29%5E2%2B%20%28221221-374374%29%5E2%29%5D%5C%5C%0A%3D%201.0828%20%5Ctimes%2010%5E%7B10%7D%0A)
Then standard deviation =
Answer: expression 1,3 and 4 are equivalent to 0.75t-21.
Step-by-step explanation:
Expression 1
3/4t-21
= 0.75t - 21
Expression 2
3/4( t-21)
Multiply through by 0.75
= 0.75 ( t - 21 )
= 0.75t - 15.75
Expression 3
0.75( t-28)
Multiply through by 0.75
= 0.75t - 21
Expression 4
t-0.25t-21
let t = 1
1-0.25t - 21
= 0.75t - 21
expression 1,3 and 4 are equivalent to 0.75t-21.
You need to provide the number line
Ashes I think it u do get ashes
Answer:
60%
Step-by-step explanation:
8-5=3
3/5=0.6 and 0.6 = 60%
so 3 is 60% or 5
so 5+3 is a 60% increase
