Answer:
<h2><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>2x</u></em></h2>
Step-by-step explanation:
= <em><u>2x × 2x × 2x (In expanded notation form) (Ans)</u></em>
-9/10
thats the correct answer but you dont have that choice on your number line so???
Answer:
10.4feet
Step-by-step explanation:
The set up wil form a right triangle
Length of the ramp is the hypotenuse
The length of the end of the ramp from the base= 10 feet (adjacent)
Angle of elevation = 15 degrees
Required
Length of the ramp
Using SOH CAH TOA
Cos theta = adj/hyp
cos 15 = 10/L
L = 10/cos15
L = 10/0.9659
L = 10.35
L ≈ 10.4 feet
Hence the length of the ramp is 10.4feet
14.4166667 feet (14 feet 5 inches)
Answer:
The equation is 4x + 3 ....
