By using the first number mulitiply
Answer:
20 gallons were used from the tank with the octane rating of 80.
Step-by-step explanation:
Given : One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. To obtain a mixture of 60 gallons with an octane rating of 120.
To find : How many gallons should be used from the tank with the octane rating of 80?
Solution : Let x be the volume of gas whose octane rating is 140 and
y be the volume of gas whose octane rating is 80.
Then, we form the equation as:
(1) 

or
.........[3]
(2) 
Now multiply equation (2) by 4
...........[4]
Subtract (4) from (3)



Put x in equation [4] we get,





Therefore, x=40 and y=20
So, 20 gallons were used from the tank with the octane rating of 80.
Y-3=-3y-43
4y-3=-43
4y=-46
y=-11.5
9514 1404 393
Answer:
Step-by-step explanation:
Like terms are ones with the same variable (or set of variables). Here, any x-terms are "like" terms. They are combined by adding their coefficients.
4x +4x +4x +4x = x(4+4+4+4) = 16x
-7x +4 +3x = x(-7+3) +4 = -4x +4
3x +5x +8 = x(3+5) +8 = 8x +8
4x +4x = x(4+4) = 8x
Answer:
Question 1: 4.5(10^−7)(2(10^4))
=
9/1000
(Decimal: 0.009)
Question 2:
mass of neutron/mass of electron = 2*10-24/(9*10-28)
2x10^(-24)/9x10^(-28)
d is closest.
Question 3:
4(10^3)(12(10^5))
=4000*1200000
=4*1000*12*100000
=(4*12)*(1000*100000)
=48*100000000
=4800000000
And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!
<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em><em> </em><em>if</em><em> </em><em>so</em><em> </em><em>pls</em><em> </em><em>mark</em><em> </em><em>brainliest</em><em> </em><em>and</em><em> </em><em>heart</em><em>/</em><em>rate</em><em>!</em>