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dlinn [17]
3 years ago
9

How many solutions are on this graph?

Mathematics
2 answers:
Leya [2.2K]3 years ago
7 0

Answer:

3

Step-by-step explanation:

the 3 places the lines cross are solutions

klemol [59]3 years ago
6 0

Answer:

There are three intersections on the graph, therefore there are three solutions to the system

Step-by-step explanation:

You might be interested in
There are 150 children in middle school.30% of the students are 6th graders. How many 6th graders are at CPCS?
IceJOKER [234]

Answer:

45 children

Step-by-step explanation:

30% of 150=45

6 0
3 years ago
Read 2 more answers
a) What is an alternating series? An alternating series is a whose terms are__________ . (b) Under what conditions does an alter
andriy [413]

Answer:

a) An alternating series is a whose terms are alternately positive and negative

b) An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|, converges if 0< b_{n+1} \leq b_n for all n, and \lim_{n \to \infty} b_n = 0

c) The error involved in using the partial sum sn as an approximation to the total sum s is the remainder Rn = s − sn and the size of the error is bn + 1

Step-by-step explanation:

<em>Part a</em>

An Alternating series is an infinite series given on these three possible general forms given by:

\sum_{n=0}^{\infty} (-1)^{n} b_n

\sum_{n=0}^{\infty} (-1)^{n+1} b_n

\sum_{n=0}^{\infty} (-1)^{n-1} b_n

For all a_n >0, \forall n

The initial counter can be n=0 or n =1. Based on the pattern of the series the signs of the general terms alternately positive and negative.

<em>Part b</em>

An alternating series \sum_{n=1}^{\infty} a_n = \sum_{n=1}^{\infty} (-1)^{n-1} b_n where bn = |an|  converges if 0< b_{n+1} \leq b_n for all n and \lim_{n \to \infty} b_n =0

Is necessary that limit when n tends to infinity for the nth term of bn converges to 0, because this is one of two conditions in order to an alternate series converges, the two conditions are given by the following theorem:

<em>Theorem (Alternating series test)</em>

If a sequence of positive terms {bn} is monotonically decreasing and

<em>\lim_{n \to \infty} b_n = 0<em>, then the alternating series \sum (-1)^{n-1} b_n converges if:</em></em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

then <em>\sum_{n=1}^{\infty}(-1)^{n-1} b_n  converges</em>

<em>Proof</em>

For this proof we just need to consider the sum for a subsequence of even partial sums. We will see that the subsequence is monotonically increasing. And by the monotonic sequence theorem the limit for this subsquence when we approach to infinity is a defined term, let's say, s. So then the we have a bound and then

|s_n -s| < \epsilon for all n, and that implies that the series converges to a value, s.

And this complete the proof.

<em>Part c</em>

An important term is the partial sum of a series and that is defined as the sum of the first n terms in the series

By definition the Remainder of a Series is The difference between the nth partial sum and the sum of a series, on this form:

Rn = s - sn

Where s_n represent the partial sum for the series and s the total for the sum.

Is important to notice that the size of the error is at most b_{n+1} by the following theorem:

<em>Theorem (Alternating series sum estimation)</em>

<em>If  \sum (-1)^{n-1} b_n  is the sum of an alternating series that satisfies</em>

<em>i) 0 \leq b_{n+1} \leq b_n \forall n</em>

<em>ii) \lim_{n \to \infty} b_n = 0</em>

Then then \mid s - s_n \mid \leq b_{n+1}

<em>Proof</em>

In the proof of the alternating series test, and we analyze the subsequence, s we will notice that are monotonically decreasing. So then based on this the sequence of partial sums sn oscillates around s so that the sum s always lies between any  two consecutive partial sums sn and sn+1.

\mid{s -s_n} \mid \leq \mid{s_{n+1} -s_n}\mid = b_{n+1}

And this complete the proof.

5 0
4 years ago
In Carna's desk drawer, there are 16 paper clips and 20 elastic bands. In Noelia's office supply tray, there are 10 paper clips
Nimfa-mama [501]

Answer:

Carna has a lower ratio of paper clips to elastic bands

0.2

Step-by-step explanation:

step one

given data

In Carna's desk drawer

number of paper clips 16

number of elastic band= 20

ratio of paper clips to elastic bands

16:20= 1/5 =0.2

Noelia's office supply tray

number of paper clips 10

number of elastic band= 13

ratio of paper clips to elastic bands

10:13= 0.76

Carna has a lower ratio of paper clips to elastic bands

0.2

5 0
3 years ago
One pound of candies costs $3.50.<br><br> How much will we have to pay for 4.5 lb?
Inessa [10]

Answer:

$15.75

Step-by-step explanation:

Multiply the cost of one pound, 3.50 times how many we want, 4.5

3.5×4.5=15.75

5 0
3 years ago
Read 2 more answers
A new school has x day students and y boarding students.
guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as x + 2y\geq 1200.​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are \$600 a term.

So, the fees for x day students are \$600x a term.

The fees for a boarding student are \$1200 a term.

The fees for y boarding student are \$1200y a term.

Total fees for x day students and y boarding student is:

\text{Total fees}=600x+1200y

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

600x+1200y\geq 720000

600(x+2y)\geq 720000

Divide both sides by 600.

\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}

x+2y\geq 1200

Hence proved.

3 0
3 years ago
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