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LiRa [457]
3 years ago
5

What is the value of x

Mathematics
1 answer:
Goryan [66]3 years ago
5 0

Answer:

20

Step-by-step explanation:

Those angles are the same so you can put them in an equation like this:

x + 60 = 4x

Then you subtract x from both sides to get variables on one side and constants on the other:

60 = 3x

Now divide by three to find what just x is:

20 = x

And there you go <3

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Hi please i nedd help with these questions .
Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}

division sign means that we flip the fraction

\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}

now we can multiply all the constants together and all variables

m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}

now we can combine all the parts

\frac{3u^3v}{16m^2}

#2:

\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}

\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}

a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18

\frac{18b^3}{c^4}

3 0
3 years ago
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What is the solution to this system?
katovenus [111]
The solution is where the two lines meet. From the the graph, it looks like
(1, -1)
6 0
3 years ago
Temperature
RSB [31]
A because -16 is colder then all the other temperatures. Hope this helped
7 0
3 years ago
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Question 7 of 10
larisa [96]

Answer:

13

Step-by-step explanation:

The diagonals of rectangle are equal in length.

4 0
3 years ago
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Give an example of each of the following, or state that such a request is impossible by referencing the proper theorem(s): (a) s
aev [14]

Answer:

There are many examples for the first request, but none for the second.

Step-by-step explanation:

a) There is a theorem which states that the sum of two convergent sequences is convergent, so any pair of convergent sequences (xn), (yn) will work (xn=1/n, yn=2/n, xn+yn=3/n. All of these converge to zero)

If you meant (xn) and (yn) to be both divergent, we can still find an example. Take (xn)=(n²) and (yn)=(1/n - n²). Then (xn) diverges to +∞ (n² is not bounded above and it is increasing), (yn) diverges to -∞ (1/n -n² is not bounded below, and this sequence is decreasing), but (xn+yn)=(1/n) converges to zero.

b) This is impossible. Suppose that (xn) converges and (xn+ýn) converges. Then (-xn) converges (scalar multiples of a convvergent sequence are convergent). Now, since sums of convergent sequences are convergent, (xn+yn+(-xn))=(yn) is a convergent sequence. Therefore, (yn) is not divergent and the example does not exist.

5 0
4 years ago
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