When you have something like this, all you need to do is substitute the values, the last is for what value of x
For the first one;
((x^2+1)+(x-2))(2)
(x^2+x-1)(2)
(2)^2+(2)-1
4+2-1
5
For the second one;
((x^2+1)-(x-2))(3)
(x^2-x+3)(3)
(3)^2-(3)+3
9-3+3
9
For the last one;
3(x^2+1)(7)+2(x-2)(3)
3((7)^2+7)+2((3)-2)
3(49+7)+2(3-2)
3(56)+2(1)
168+2
170
Answer:
6(3h+5k)
Step-by-step explanation:
18h+30k
Factors of 18:
1, 2, 3, 6, 9, 18
Factors of 30:
1, 2, 3, 5, 6, 10, 15, 30
GCF of 18 and 30: 6
18h+30k = 6(3h+5k)
Check your answer:
6(3h+5k)
6(3h) + 6(5k)
18h + 30k
Hope this helps!
Answer:
1).false 2). false 3).true 4). true
Step-by-step explanation:
1).All whole numbers are integers, so s...” That's right! All whole numbers are integers, so since 0 is a whole number, 0 is also an integer.
3).. Integers include all whole numbers and their negative counter part e.g. … -4, -3, -2, -1, 0,1, 2, 3, 4,… Where a and b are both integers. is a rational number but not an integer. 4). All integers are rational number. Since we can rewrite an integer into a fractional form by diving it by 1. For example, 4=41 4 = 4 1 . But not all rational numbers are integer.
