How do I do this. Please help

The expression 27.50+ 0.11x models the monthly cost in dollars of a phone plan. In the

AlladinOne [14]

Answer: 31.57

Step-by-step explanation: If x is 37, that would mean 0.11 x 37 and that equals 4.07. Then you would add 27.50 and 4.07 and get 31.57.

6 0

3 years ago

X 2 + 6x + 8 = 0 Final answer: x = x = ____

mezya [45]

-1 im not sure if you meant 2x+6x+8=0

6 0

4 years ago

Match the parabolas represented by the equations with their foci.

Elenna [48]

Function 1 $f(x)=- x^{2} +4x+8$

First step: Finding when $f(x)$ is minimum/maximum
The function has a negative value $x^{2}$ hence the $f(x)$ has a maximum value which happens when $x=- \frac{b}{2a}=- \frac{4}{(2)(1)}=2$ . The foci of this parabola lies on $x=2$ .

Second step: Find the value of y-coordinate by substituting $x=2$ into $f(x)$ which give $y=- (2)^{2} +4(2)+8=12$

Third step: Find the distance of the foci from the y-coordinate
$y=- x^{2} +4x+8$ - Multiply all term by -1 to get a positive $x^{2}$
$-y= x^{2} -4x-8$ - then manipulate the constant of y to get a multiply of 4
$4(- \frac{1}{4})y= x^{2} -4x-8$
So the distance of focus is 0.25 to the south of y-coordinates of the maximum, which is $12- \frac{1}{4}=11.75$

Hence the coordinate of the foci is (2, 11.75)

Function 2: $f(x)= 2x^{2}+16x+18$

The function has a positive $x^{2}$ so it has a minimum

First step - $x=- \frac{b}{2a}=- \frac{16}{(2)(2)}=-4$
Second step - $y=2(-4)^{2}+16(-4)+18=-14$
Third step - Manipulating $f(x)$ to leave $x^{2}$ with constant of 1
$y=2 x^{2} +16x+18$ - Divide all terms by 2
$\frac{1}{2}y= x^{2} +8x+9$ - Manipulate the constant of y to get a multiply of 4
$4( \frac{1}{8}y= x^{2} +8x+9$

So the distance of focus from y-coordinate is $\frac{1}{8}$ to the north of $y=-14$
Hence the coordinate of foci is (-4, -14+0.125) = (-4, -13.875)

Function 3: $f(x)=-2 x^{2} +5x+14$

First step: the function's maximum value happens when $x=- \frac{b}{2a}=- \frac{5}{(-2)(2)}= \frac{5}{4}=1.25$
Second step: $y=-2(1.25)^{2}+5(1.25)+14=17.125$
Third step: Manipulating $f(x)$
$y=-2 x^{2} +5x+14$ - Divide all terms by -2
$-2y= x^{2} -2.5x-7$ - Manipulate coefficient of y to get a multiply of 4
$4(- \frac{1}{8})y= x^{2} -2.5x-7$
So the distance of the foci from the y-coordinate is - $\frac{1}{8}$ south to y-coordinate

Hence the coordinate of foci is (1.25, 17)

Function 4: following the steps above, the maximum value is when $x=8.5$ and $y=79.25$ . The distance from y-coordinate is 0.25 to the south of y-coordinate, hence the coordinate of foci is (8.5, 79.25-0.25)=(8.5,79)

Function 5: the minimum value of the function is when $x=-2.75$ and $y=-10.125$ . Manipulating coefficient of y, the distance of foci from y-coordinate is $\frac{1}{8}$ to the north. Hence the coordinate of the foci is (-2.75, -10.125+0.125)=(-2.75, -10)

Function 6: The maximum value happens when $x=1.5$ and $y=9.5$ . The distance of the foci from the y-coordinate is $\frac{1}{8}$ to the south. Hence the coordinate of foci is (1.5, 9.5-0.125)=(1.5, 9.375)

8 0

3 years ago

Solve for x: 5(x-2)+7=65-4(5x-8)<br> SHOW STEPS PLZZZZZZ HELP

miskamm [114]

5(x-2)+7=65-4(5x-8)

We move all terms to the left:

5(x-2)+7-(65-4(5x-8))=0

We multiply parentheses

5x-(65-4(5x-8))-10+7=0

We calculate terms in parentheses: -(65-4(5x-8)), so:

65-4(5x-8)

determiningTheFunctionDomain

-4(5x-8)+65

We multiply parentheses

-20x+32+65

We add all the numbers together, and all the variables

-20x+97

Back to the equation:

-(-20x+97)

We add all the numbers together, and all the variables

5x-(-20x+97)-3=0

We get rid of parentheses

5x+20x-97-3=0

We add all the numbers together, and all the variables

25x-100=0

We move all terms containing x to the left, all other terms to the right

25x=100

x=100/25

x=4

6 0

3 years ago

Read 2 more answers

If 150 represents 3/4 of students at central. What is the total student population at central?

yaroslaw [1]

200

Because 50 equals 1/4
then 100 equals 2/4
then 150 equals 3/4
and at last 200 equal 4/4

5 0

3 years ago