Question

Which equation represents a line that passes through the two points in the table?

Answer 1

Answer:

$\large\boxed{A.\ y-3=\dfrac{2}{3}(x-3)}$

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (3, 3) and (6, 5).

Substitute:

$m=\dfrac{5-3}{6-3}=\dfrac{2}{3}$

Take the point (3, 3):

$y-3=\dfrac{2}{3}(x-3)$