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butalik [34]
3 years ago
7

Afla suma numerelor 170 si238 572 si279 395si 123 628si 229 ​

Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer:

Step-by-step explanation:

170 + 238 =408

572 + 279 =851

395 + 123 =518

628 + 229 =857

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Describe the following variation: y/x2=5
Firdavs [7]
We are asked to describe the variation \displaystyle{ \frac{y}{x^2}=5, 

that is y=5x^2

for x≠0, in which case x=y=0, we distinguish the following intervals:

I   = (-infinity, -1]
II  = (-1, 0)
III = (0, 1)
III = [1, infinity)

Case I, consider the cases (examples)   x= -5, and x= -6

5(-6)^2\ \textgreater \ 5(-5)^2, so we can conclude that the greater the x, the smaller the y.

Case II, consider x= -1/2 < x=-1/3

5(-\frac{1}{2})^2= \frac{5}{4}\\\\ 5(-\frac{1}{3})^2= \frac{5}{9}\\\\\frac{5}{9}\ \textless \  \frac{5}{4}

thus, the greater the x, the smaller the y.


Case III, consider the cases (examples)   x= 5, and x= 6

5(6)^2\ \textgreater \ 5(5)^2, so we can conclude that the greater the x, the greater the y.

Case III, consider x= 1/3 < x=1/2

5(\frac{1}{2})^2= \frac{5}{4}\\\\ 5(\frac{1}{3})^2= \frac{5}{9}\\\\\frac{5}{9}\ \textless \ \frac{5}{4}

thus, the greater the x, the greater the y.


Conclusion:

y=0 only if x is 0. Otherwise y>0 always:

for x<0,   x and y are inversely proportional

for x>0,   x and y are directly proportional.


Remark, an other possible consideration in cases could be x<0 and x>0 only.


Remark, 
another approach is considering the graph of y=5x^2, which is a parabola, with the vertex at (0, 0) opening upwards.

From the graph we can find the same conclusion. That is we can see that the farer we get away from the y-axis, in both direction, the larger the values of y become.

4 0
3 years ago
A group of climbers begin climbing at an elevation of 5000 feet and ascend at a steady rate of 1500 vertical feet per hour. This
KatRina [158]

Answer:

Linear function:y=1500x+5000

x- Independent variable

y- Dependent variable

Step-by-step explanation:

We are given that

Climbers start climbing at an elevation of height =5000 ft

The steady rate at which climbers start climbing=1500 ft/h

We have to find the independent variable and dependent variable.

Let time taken by climbers=x hours

In 1 hour, climbers cover distance =1500 ft

In x hours , climber cover distance=1500x ft

According to question

The total distance y covered by climber in x hours

y=1500x+5000

This is required linear function.

We can see that

x does not depend on any other quantity.Therefore, x is independent variable .

When the value of x changes then the value of y is also change.

It means the value of y depends on the value of x.

Therefore, y is dependent variable.

8 0
4 years ago
The graph below shows the height of a kicked soccer ball f(x), in feet, depending on the distance from the kicker x, in feet: Pa
Advocard [28]

the complete question in the attached figure

part A

the x intercept 0 is the point where the ball was hit, the x intercept 20 is the point where the ball fell back to the ground, 20 feet away from the kicker.

<span>the function is increasing in the interval x∈(0, 10) and decreasing in x∈(10, 20) </span>
this means that the height is increasing in the interval  (0, 10) and decreasing as x goes through the interval (10,20)
the distance from the kicker is increasing during the whole interval (0, 20)

part B

the rate of change represents the slope of the secant line from A to B. It approximates the rate at which f(x) decreases or increases in the interval 

x =[A, B]

from x = 22 to x = 26-------------- > the function does not exist


5 0
3 years ago
Write a rule that represents the function. <br> (1,1/2),(2,1/4),(3.1/8),(4,1/16),(5,1/32)
ratelena [41]

Answer:

Step-by-step explanation:

. cubesi, 20,64. AV 1,6,11,16... Add 5. 1, 2, 4, 8. . Multiply 2. $2,9,28,65... cubes add 1. 31,49,16 ...

5 0
3 years ago
Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standa
inessss [21]

Answer:

a) 0.4164

Step-by-step explanation:

Mean lifespan (μ) = 18.8 days

Standard deviation (σ) = 2 days

For any given lifespan 'X', the z-score is:

z=\frac{X- \mu}{\sigma} \\z=\frac{X- 18.8}{2}

For X=12.04 days:

z=\frac{12.04 - 18.8}{2} \\z=-3.38

A z-score of -3.38 falls in the 0.036-th percentile of a normal distribution.

For X=18.38 days:

z=\frac{18.38 - 18.8}{2} \\z=-0.21

A z-score of -3.38 falls in the 41.68th percentile of a normal distribution.

The probability that a butterfly lives between 12.04 and 18.38 days is

P=41.68-0.036\\P=41.64\%\ or\ 0.4164

6 0
3 years ago
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