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butalik [34]
3 years ago
7

Afla suma numerelor 170 si238 572 si279 395si 123 628si 229 ​

Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer:

Step-by-step explanation:

170 + 238 =408

572 + 279 =851

395 + 123 =518

628 + 229 =857

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Which shows the factored form of x2 – 12x – 45? (x 3)(x – 15) (x – 3)(x – 15) (x 3)(x 15) (x – 3)(x 15).
Aleksandr [31]

The factors of the quadratic equation are (x+3) and (x-15).

<h2 /><h2>Given to us</h2>
  • x^2-12x-45\\

<h3>To find</h3>

The factors of x^2-12x-45\\.

<h3 /><h3>Solution</h3>

x^2-12x-45\\

As we can see in the quadratic equation the value of ac is -45x². therefore, we need to divide -12x into two parts such that their sum must give -12x and their product gives us -45x².

therefore, dividing -12x into -15x and 3x,

x^2-15x+3x-45\\

Taking common out,

x^2-15x+3x-45\\x(x-15)+3(x-15)\\(x+3)(x-15)

Hence, the factors of the quadratic equation are (x+3) and (x-15).

Learn more about quadratic equations:

brainly.com/question/2263981

3 0
2 years ago
How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?
liraira [26]

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

We have total digits as 0 to 9.

4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= 10(9)(8)(7)\\=5040

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

3 0
3 years ago
What is the solution to the inequality 2 + 5x &gt; 12?
Alexxx [7]
Im not in expert at this but i did the best i could im 80% sure this is the anser if not im sorry    x > 30 
6 0
3 years ago
Read 2 more answers
Consider the hypotheses below. Upper H 0​: mu equals 50 Upper H 1​: mu not equals 50 Given that x overbar equals 60​, s equals 1
Neko [114]

Answer:

We conclude that  \mu\neq 50.

Step-by-step explanation:

We are given that x bar = 60​, s = 12​, n = 30​, and alpha = 0.10

Also, Null Hypothesis, H_0 : \mu = 50

Alternate Hypothesis, H_1 : \mu \neq 50

The test statistics we will use here is;

                    T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~  t_n_-_1

where, X bar = sample mean = 60

              s = sample standard deviation = 12

              n = sample size = 30

So, Test statistics = \frac{60-50}{\frac{12}{\sqrt{30} } } ~ t_2_9

                             = 4.564

At 10% significance level, t table gives critical value of 1.311 at 29 degree of freedom. Since our test statistics is more than the critical value as 4.564 > 1.311 so we have sufficient evidence to reject null hypothesis as our test statistics will fall in the rejection region.

P-value is given by, P(t_2_9 > 4.564) = less than 0.05% {using t table}

Here also, P-value is less than the significance level as 0.05% < 10% , so we will reject null hypothesis.

Therefore, we conclude that \mu\neq 50.

7 0
3 years ago
5|x + 11 + 7 = -38<br> Absolute value equations
gogolik [260]
The answer to this question is 32
5 0
3 years ago
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