PLEASE HELP!! Solve each inequality and graph its solution.

1. A flowering plant contains its seeds inside _______.

AURORKA [14]

I believe the answer would be ovaries

7 0

3 years ago

a doctor order calls for you to administer 0.1 mg of epinephrine in stock is a 1ml ampule that contains1 mg of epinephrine cacul

Darina [25.2K]

If 1 ml of volume contains 1 mg of epinephrine, then 0.1 ml of volume contains 0.1 mg of epinephrine.

Let x be the number of ml you need.

Ratio: 1 ml is to 1 mg as x ml is to 0.1 mg

(1 ml)/(1 mg) = (x ml)/(0.1 mg)

Cross multiply.

1 * x = 1 * 0.1

x = 0.1

Answer: 0.1 ml

6 0

4 years ago

Angle 1 and angle 2 form a linear pair.if m angle =5x+9 and m angle 2=3x+11,find the measures of both angels.

lbvjy [14]

Answer: ∠1 = 109° ∠2 = 71°

Step-by-step explanation:

If the two angles form a linear pair, then their sum is 180°

∠1 + ∠2 = 180°

(5x + 9) + (3x + 11) = 180

8x + 20 = 180

8x = 160

x = 20

∠1 = 5x + 9

= 5(20) + 9

= 100 + 9

= 109

∠2 = 3x + 11

= 3(20) + 11

= 60 + 11

= 71

CHECK:

∠1 + ∠2 = 180°

109° + 71° = 180°

180° = 180° $\checkmark$

7 0

4 years ago

write the equation of the perpendicular bisector that goes through the line segment with end points of A -1,-2 and B -2,-8

Dennis_Churaev [7]

Answer:

2x +12y = -63 . . . in standard form

y = -1/6x -21/4 . . . in slope-intercept form

Step-by-step explanation:

It is useful to find the midpoint of the segment. That is the average of the end points:

M = ((-1, -2) +(-2, -8))/2 = ((-1-2)/2, (-2-8)/2) = (-3/2, -5)

It is also useful to find the changes in coordinates from B to A:

Δ = A-B = (-1-(-2), -2-(-8)) = (1, 6)

From here, there are a couple of ways you can write the equation of the perpendicular line.

__

One way is to use the Δ values to compute the slope of the segment. The perpendicular line will have a slope that is the negative reciprocal of that.

Δy/Δx = 6/1 = 6

m = -1/6 . . . . . slope of the perpendicular line

Now we have a point and a slope for the desired line, so we can use a point-slope form of the equation for a line:

y = m(x -h) +k

y = (-1/6)(x -(-3/2)) +(-5)

y = (-1/6)x -21/4 . . . . . . . . eliminate parentheses; point-slope form

__

Another way to write the perpendicular line is to use the Δ values directly as coefficients in the standard form equation:

Δx(x -h) +Δy(y -k) = 0

1(x -(-3/2)) + 6(y -(-5)) = 0 . . . substitute values

x +6y +31.5 = 0 . . . . . . . . . . .collect terms

2x +12y = -63 . . . . . . . . . . . . multiply by 2, put in standard form

7 0

3 years ago

Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul

anyanavicka [17]

Answer:

5536 calculators

Step-by-step explanation:

We integrate the function dx/dt to obtain the number of new calculators between beginning of the 3rd week and end of week 4. Note that beginning of 3rd week is the same as end of 2nd week. So, $\int\limits^4_2 {\frac{dx}{dt} } \, dx$ = $\int\limits^4_2 {5000 (1 - \frac{100}{(t +12)^{2} }) } \, dx$

Let u = t + 12, then $\frac{du}{dt}$ = 1. So, du = dt. We also change the limits of our integration. So, when t = 2, u = 2 + 12 = 14 and when t = 4, u = 4 + 12 = 16

Then $\int\limits^4_2 {5000(1 -\frac{100}{(t+12)^{2} } )} \, dx$ = ∫₁₄¹⁶ ${5000(1 -\frac{100}{u^{2} } )} \, du = 5000[ u + \frac{100}{u} ]$ ₁₄¹⁶ = $5000[16 + \frac{100}{16} - (14 + \frac{100}{14} )] = 5000 [16 - 14 + \frac{100}{16} - \frac{100}{14} ] = 5000 [2 + \frac{100}{16} - \frac{100}{14} ] = 5535.7$

≈ 5536 calculators

3 0

4 years ago