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lions [1.4K]
3 years ago
9

PLEASE HELP!! Solve each inequality and graph its solution.

Mathematics
1 answer:
12345 [234]3 years ago
6 0

Answer:

the answer is b

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How to divide integers
Alona [7]
I got this I hope this is helpful. To multiply or divide signed integers, always multiply or divide the absolute values and use these rules to determine the sign of the answer:
The product of two positive integers or two negative integers is positive.
The product of a positive integer and a negative integer is negative.
8 0
2 years ago
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Anduin casts a variety of healing spells. The number of health points that each of his healing spells restores
melomori [17]
43+57+30+18+26+12=186
divide 186 by the number of healing spells (6)
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2 years ago
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Why would someone want to factor a polynomial? Provide real-world examples of different questions we can answer or factors we ca
IgorC [24]

Factoring is a common mathematical process used to break down the factors, or numbers, that multiply together to form another number. Some numbers have multiple factors.

<u>Explanation:</u>

Factoring polynomials involves breaking up a polynomial into simpler terms (the factors) such that when the terms are multiplied together they equal the original polynomial. Factoring helps solve complex equations so they are easier to work with. Factoring polynomials includes: Finding the greatest common factor.

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6 0
3 years ago
I WILL GIVE BRAINLIEST<br> Who will get this question right
Ksju [112]
If 101 use 3/5 for his Artwork, then the space remaining for 102 is:

5/5 - 3/5 = 2/5 (since the whole wall represents 100% or 5/5 or 1)

6 0
3 years ago
Grace wants to find the probability of a family of 3 children having 2 boys and 1 girl. Use a tree diagram to list the possibili
pychu [463]

Answer:

Step-by-step explanation:

My approach was to draw out the probabilities, since we have 3 children, and we are looking for 2 boys and 1 girl, the probabilities can be Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy. So a 2/3 chance if you think about it, your answer 2/3 can't be correct. If we assume that boys and girls are born with equal probability, then the probability to have two girls (and one boy) should be the same as the probability to have two boys and one girl. So you would have two cases with probability 2/3, giving an impossible 4/3 probability for both cases. Also, your list "Boy-Boy-Girl, Boy-Girl-Boy, and Girl-Boy-Boy" seems strange. All of those are 2 boys and 1 girl, so based on that list, you should get a 100 percent chance. But what about Boy-Girl-Girl, or Girl-Girl-Girl? You get 2/3 if you assume that adjacencies in the (ordered) list are important, i.e., "2 boys and a girl" means that the girl was not born between the boys.

5 0
1 year ago
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