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liberstina [14]
3 years ago
15

Define activation energy.Activation energy is Define activation energy.the energy barrier that must be surmounted in order for t

he reactants to transform into products.the energy difference between the reactants and the products.the energy released by the reactants while transforming into products.the energy released by the products while transforming into reactant
Chemistry
1 answer:
Natali [406]3 years ago
5 0

Answer:

the energy barrier that must be surmounted in order for the reactants to transform into products.

Explanation:

When we draw a reaction profile, there is always a hump that is found between the reactants and products. This hump is called the activation energy.

The activation energy of a reaction stands as a sort of barrier between reactants and products which must be surmounted before the reactants are converted into products.

Only reactants that possess the activation energy can be converted from reactants to products.

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It does not have a regular composition.

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From the attached phase diagram, one can easily make out the phase in which water exists. Matter generally exists in three physical states which are solid, liquid and gas. Water is a unique compound that can exists in these three states at a given temperature and pressure.

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A volume of 40.0 mLmL of aqueous potassium hydroxide (KOHKOH) was titrated against a standard solution of sulfuric acid (H2SO4H2
Anni [7]

<u>Answer:</u> The concentration of KOH solution is 1.215 M

<u>Explanation:</u>

For the given chemical equation:

2KOH(aq.)+H_2SO_4(aq.)\rightarrow K_2SO_4(aq.)+2H_2O(l)

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is KOH.

We are given:

n_1=2\\M_1=1.50M\\V_1=16.2mL\\n_2=1\\M_2=?M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 1.50\times 16.2=1\times M_2\times 40.0\\\\M_2=\frac{2\times 1.50\times 16.2}{1\times 40.00}=1.215M

Hence, the concentration of KOH solution is 1.215 M

3 0
4 years ago
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