According to the phase diagram for water, how is the state of water determined?
2 answers:
Explanation:
From the attached phase diagram, one can easily make out the phase in which water exists. Matter generally exists in three physical states which are solid, liquid and gas. Water is a unique compound that can exists in these three states at a given temperature and pressure.
From the attached phase diagram,
- point O is the triple point where the three phases of pure substance co-exists.
- The areas between the curves points at a single phase of matter. Y is a water vapor.
- The lines on the curve denotes two equilibrium phases. For example; X is a phase contain ice and melt water.
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The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.
<h3>Dilution</h3>According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:
Where is the molarity before dilution,
is the volume before dilution,
is the molarity after dilution, and
is the volume after dilution.
In this case, = 0.774 M,
= 10.0 mL,
= 100 mL.
=
= 0.774 x 10/100
= 0.0774 M
Thus, the new concentration of the sodium sulfide solution would be 0.0774 M.
Mole of the final solution: 0.0774 x 0.1 = 0.00774 mol
Sodium sulfide formula = --->
Equivalent mole of sodium ion = 0.00774 x 2
= 0.01548 mol
The concentration of sodium ions = mol/volume
= 0.01548/0.1
= 0.1548 M
In other words, the concentration of the sodium ions in the diluted solution would be 0.1548 M.
More on dilution can be found here: brainly.com/question/21323871
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