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Ksenya-84 [330]
3 years ago
7

If an element has three isotopes with known masses, what other information is needed to find the average atomic mass of the elem

ent
Chemistry
2 answers:
Ber [7]3 years ago
6 0

The abundance percentage of each isotope

Art [367]3 years ago
5 0
You need to find the abundance. Then, multiply the abundance by 100, and add that to the mass for each isotope. Basically, for each isotope, take the percentage abundance and add it to the mass. Multiply each calculation of these together to get your average atomic mass,
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When 20.00 mL of an unknown monoprotic acid is titrated with 0.125 M NaOH, it takes 15.00 mL to reach the endpoint. What is the
ohaa [14]

Answer:

About 0.0940 M.

Explanation:

Recall that NaOH is a strong base, so it dissociates completely into Na⁺ and OH⁻ ions. Because the acid is monoprotic, we can represent it with HA. Thus, the reaction between HA and NaOH is:


\displaystyle \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)} \longrightarrow \text{H$_2$O}_\text{($\ell$)} + \text{A}^-_\text{(aq)}

Using the fact that it took 15.00 mL of NaOH to reach the endpoint, determine the number of HA that was reacted with:

\displaystyle \begin{aligned} 15.00\text{ mL} &\cdot \frac{0.125\text{ mol NaOH}}{1\text{ L}} \cdot \frac{1\text{ L}}{1000\text{ mL}} \\ \\  &\cdot \frac{1\text{ mol OH}^-}{1\text{ mol NaOH}} \cdot \frac{1\text{ mol HA}}{1\text{ mol OH}^-}\\ \\  & = 0.00188\text{ mol HA}\end{aligned}

Therefore, the molarity of the original solution was:


\displaystyle \left[ \text{HA}\right] = \frac{0.00188\text{ mol}}{20.00\text{ mL}} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 0.0940\text{ M}

In conclusion, the molarity of the unknown acid is about 0.0940 M.

3 0
2 years ago
How many nitrogen atoms are in 2.79 mo.of NH3
alexandr1967 [171]
1 mol of any particles has 6.02 * 10 ²³ particles.

If we look at 1 NH3 (1 mol NH3 or 1 molecule NH3), we can see that 1 molecule NH3 has 1 atom of N and 3 atoms of H; also 1 mole of NH3 has 1 mole of N atoms and 3 moles of H atoms.

So, 1 mol of NH3 has 1 mol of N atoms,
 and 2.79 mol NH3 have 2.79 mol of N atoms.

2.79 mol of N atoms* 6.02 * 10 ²³ N atoms/ 1 mol N atoms = 1.68*10²⁴ N-atoms 

 Answer is 1.68*10²⁴ N-atoms. 
5 0
3 years ago
Please help me out...
liq [111]

Answer:

Explanation:

To convert from grams to atoms, first divide by the molar mass, the multiply by 6.022*10^23.

To convert from moles to mass, multiply by the molar mass of the element.

Hope this helps!

-Emma Victoria

4 0
3 years ago
Convert 205 L to ul.
Sloan [31]

Answer: 205000000 microliter

Hope this helps!

8 0
3 years ago
Read 2 more answers
I need help with #3 name the compound
ioda
4-ethyl-3-methyl 1 hexane
4 0
3 years ago
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