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1 year ago

What is the area of this shape?

Mathematics

2 answers:

Akimi4 [234]1 year ago

4 0

Answer:

144

Step-by-step explanation:

The shape is a trapezoid.

Add 6 and 112, which is eighteen

divide eighteen by 2, which is 9

Finally, multiply 9 and sixteen which is 144

Eddi Din [679]1 year ago

4 0

Area =1/2(sum of parallel base) x (perpendicular height)

A=(1/2)(a+b)h
A=(1/2)(6+12)(16)
A= (1/2)(18)(16)
A=(9 x 16)
A=144 in2

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A ball is drawn at random from a box containing 12 red,18

Lubov Fominskaja [6]

Answer:

For a: The probability of getting a red or blue ball is 0.48

For b: The probability of getting a white, blue or orange ball is 0.81

For c: The probability of getting neither white or orange ball is 0.48

Step-by-step explanation:

Probability is defined as the extent to which an event is likely to occurs. It is measured by the ratio of the favorable outcomes to the total number of possible outcomes.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of favorable outcomes}}$ .......(1)

We are given:

Number of red balls in a box = 12

Number of white balls in a box = 18

Number of blue balls in a box = 19

Number of orange balls in a box = 15

Total balls in a box = [12 + 18 + 19 + 15] = 64

For a:

Number of favorable outcomes (ball must be red or blue) = [12 + 19] = 31

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a red or blue ball}=\frac{31}{64}=0.48$

For b:

Number of favorable outcomes (ball must be white or blue or orange) = [18 + 19 + 15] = 52

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or blue or orange ball}=\frac{52}{64}=0.81$

For c:

Number of favorable outcomes (ball must be white or orange) = [18 + 15] = 33

Total number of outcomes = 64

Putting values in equation 1, we get:

$\text{Probability of getting a white or orange ball}=\frac{33}{64}=0.52$

Probability of getting a ball which is neither white or orange = [1 - (Probability of getting a white or orange ball)] = [1 - 0.52] = 0.48

7 0

2 years ago

-4(2x-3)>-28 please i need this result

Len [333]

-4 (2x - 3) > -28

Divide by -4 on both sides. Since we're dividing by a negative, we need to switch the sign.

2x - 3 < 7

Add 3 to both sides

2x < 10

Divide by 2 on both sides

x < 5

3 0

2 years ago

What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint

leonid [27]

The right answer is c. –2.24, 2, 2.24

This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.

1. Using a graphing calculator.

We have the following polynomial equation:

$x^3-5x+5=2x^2-5$

By ordering this equation we have:

$x^3-2x^2-5x+10=0$

So, we can say that this equation comes from a function given by:

$f(x)=x^3-2x^2-5x+10$

Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of $f(x)$ which are:

$x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236$

Finally, rounding noninteger roots to the nearest hundredth we have:

$\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}$

2. Using a system of equations.

The ordered equation is:

$x^3-2x^2-5x+10=0$

By arranging to factor out we have:

$x^3-5x-2x^2+10=0$

Then, by factoring:

$x(x^2-5)-2(x^2-5)=0$

Term $(x^2-5)$ is a common factor, thus:

$(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}$