Question

WILL GIVE LOTS OF POINTS, PLEASE HELP !!!!

Answer 1

Answer:

Terminal side in 2nd Quadrant

Only sin(x) & cosec(x) are positive in 2nd Quadrant

$\sin( x ) = \frac{5}{13}$

Perpendicular=5

Base=√(13²-5²)=√(169-25)=√144=√12²=12

Hypotenuse=13

$\cos(x)= - \frac{12}{13} \\ \tan(x) = - \frac{5}{12} \\ \cosec(x) = \frac{13}{5} \\ \sec(x)= - \frac{13}{12} \\\cot(x) = - \frac{12}{5}$