A + b = 15 ..... eq 1
a – b = 12 ...... eq 2
So a = 15 – b
Substitute in eq 2 :
15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5
So a = 15 – 3/2 = 13.5
4ab = 4 x 13.5 x 1.5 = 81
Answer:
The graph should be stretched rather than become narrower.
Step-by-step explanation:
To figure this out, just create some example points.
At x = 0, your y-value will always be 0. But if you were to plug in the value 1, you would get a y-value of 1 in y=x^2, but a value of 0.5 in y=0.5x^2. If you were to plug in a value of 2, you would get a value of 4 in y=x^2, but a value of 2 in y=0.5x^2.
If you continue this pattern for a few more points, then plot them, you will see that adding a coefficient of 0.5 simply stretches the graph
The distance traveled is the hypotenuse of the right triangle formed with the ground.
sinα=400/d
d=400/sinα, we are told α=13° so
d=400/sin13 ft
d≈1778ft (to nearest whole foot)
Answer:
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
hope it helps
Answer:
The precipitation for both March and April was 8 7/8 inches below average
Step-by step explanation;
For the month of march, precipitation was 6 1/2 inches less than average
For the month of April, precipitation was 2 3/8 inches left.
Now we want to calculate how many inches less than average was precipitation in both wants
What we simply do here is to add the inches with which they were both left than average in both months
That would be;
6 1/2 + 2 3/8
= 13/2 + 19/8 = (52 + 19)/8 = 71/8 = 8 7/8 inches
